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3 years ago

12

Easy Help Please!!!!!!

1 answer:

IRISSAK [1]3 years ago

5 0

False it can only be one to take place

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Explain how transverse waves can be produced on a rope. Then describe how pieces of the rope move as waves pass.

andrew-mc [135]

Transverse waves can be produced on a rope by moving one end of the rope up and down.The movement causes motion in the particles that make up the rope and the rope itself becomes the medium. The particles move perpendicular to the propagation. The movement also causes crests(highest point of the wave) and troughs (lowest point of the wave) which move along the direction of propagation.

6 0

3 years ago

What kind of changes cause iron to rust ?

loris [4]

Answer:

ways it rust are

1.you put water on it

2.let it sit out side for about a month or 2

or

you put the iron in water still wait a month or 2 then

you got the full or sum rusty parts

Explanation:

ether way you need water, air ,and the main thing... IRON

8 0

2 years ago

PPPPPPPLLLLLLLLZZZZZZ HELP I'LL GIVE BRAINLIEST

Alex17521 [72]

Food web should be the correct answer

:)

7 0

3 years ago

Read 2 more answers

What is the empirical formula? A compound is used to treat iron deficiency in people. It contains 36.76% iron, 21.11% sulfur, an

Mandarinka [93]

Answer: The empirical formula of the compound is $Fe_1S_1O_4$

Explanation:

Empirical formula is defined formula which is simplest integer ratio of number of atoms of different elements present in the compound.

Percentage of iron in a compound = 36.76 %

Percentage of sulfur in a compound = 21.11 %

Percentage of oxygen in a compound = 42.13 %

Consider in 100 g of the compound:

Mass of iron in 100 g of compound = 36.76 g

Mass of iron in 100 g of compound = 21.11 g

Mass of iron in 100 g of compound = 42.13 g

Now calculate the number of moles each element:

Moles of iron= $\frac{36.76 g}{55.84 g/mol}=0.658 mol$

Moles of sulfur= $\frac{21.11 g}{32.06 g/mol}=0.658 mol$

Moles of oxygen= $\frac{42.13 g}{16 g/mol}=2.633 mol$

Divide the moles of each element by the smallest number of moles to calculated the ratio of the elements to each other

For Iron element = $\frac{0.658 mol}{0.658 mol}=1$

For sulfur element = $\frac{0.658 mol}{0.658 mol}=1$

For oxygen element = $\frac{2.633 mol}{0.658 mol}=4.001\approx 4$

So, the empirical formula of the compound is $Fe_1S_1O_4$

4 0

2 years ago

Read 2 more answers

Using this balanced equation: 2 NaOH + H2SO4 —> H2O + Na2SO4

pogonyaev

Answer:

266.25g

Explanation:

8 0

3 years ago