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DiKsa [7]
3 years ago
12

Easy Help Please!!!!!!

Chemistry
1 answer:
IRISSAK [1]3 years ago
5 0
False it can only be one to take place
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Answer: 2.58 days

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t=\frac{2.303}{k}\log\frac{a}{a-x}

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t = age of sample  = 6 days

a = initial amount of the reactant  =  1 g

a - x = amount left after decay process   = 0.2 g

a) to find the rate constant

6=\frac{2.303}{k}\log\frac{1.0}{0.2}

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