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guajiro [1.7K]
2 years ago
11

If .758 moles of gas occupy a volume of 80.6L, how many moles will occupy a volume of 270.9L?

Chemistry
1 answer:
egoroff_w [7]2 years ago
4 0

Answer:

n₂ = 2.55 mol

Explanation:

Given data:

Initial number of moles = 0.758 mol

Initial volume = 80.6 L

Final volume = 270.9 L

Final number of moles = ?

Solution:

Formula:

V₁/n₁ = V₂/n₂

V₁ = Initial volume

n₁ = initial number of moles

V₂ = Final volume

n₂ =  Final number of moles

now we will put the values in formula.

V₁/n₁ = V₂/n₂

80.6 L / 0.758 mol = 270.9 L/ n₂

n₂ = 270.9 L× 0.758 mol / 80.6 L

n₂ =  205.34 L.mol /80.6 L

n₂ = 2.55 mol

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A weather balloon contains 1.10X10 to the power of 5 mol of helium and has a volume of 2.70x10 to the power of 6 L at 1.00 atm p
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Explanation:

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The ideal gas law is often written as

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where P ,V and T are the pressure, volume and absolute temperature;

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