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guajiro [1.7K]
2 years ago
11

If .758 moles of gas occupy a volume of 80.6L, how many moles will occupy a volume of 270.9L?

Chemistry
1 answer:
egoroff_w [7]2 years ago
4 0

Answer:

n₂ = 2.55 mol

Explanation:

Given data:

Initial number of moles = 0.758 mol

Initial volume = 80.6 L

Final volume = 270.9 L

Final number of moles = ?

Solution:

Formula:

V₁/n₁ = V₂/n₂

V₁ = Initial volume

n₁ = initial number of moles

V₂ = Final volume

n₂ =  Final number of moles

now we will put the values in formula.

V₁/n₁ = V₂/n₂

80.6 L / 0.758 mol = 270.9 L/ n₂

n₂ = 270.9 L× 0.758 mol / 80.6 L

n₂ =  205.34 L.mol /80.6 L

n₂ = 2.55 mol

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Answer:

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Looking at the gases listed, C2H6 have the highest average kinetic energy at this temperature since it has the lowest molecular mass. This reasoning is directly derived from Graham's law of diffusion in gases.

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A hydrogen halide diffuses 1.49 times faster than HBr. This hydrogen halide is
marysya [2.9K]

To solve this problem, we must assume ideal gas behaviour so that we can use Graham’s law:

vA / vB = sqrt (MW_B / MW_A)

where,

<span>vA = speed of diffusion of A  (HBR)</span>

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HCl

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