Answer:
C6 H10 O5+ 6O2-----> 6CO2+5H2O+heat
Explanation:
There are 6 carbon atoms in reactants to balance you put coefficient 6.
This makes the oxygen in CO2 12 so to balance put 6 in oxygen in reactants.
There are 10 hydrogen atoms in reactants to balance you put 5 in front of H2O in products.
If u recheck: 6 C atoms in reactants, 6 C atoms in products.
10 H atoms in reactants, 10 H atoms in products.
17 O atoms in reactants, 17 O atoms in products.
A 0.25m solution of NaCl is defined as a solution consisting of 0.25mol NaCl dissolved in 1kg water:
Which choice fits this definition: None does. I suggest that you recheck the data you have submitted - you have a mixture of moles, mass, etc and it is easy to make a mistake.
d) looks promising if it was: 1.0 mol NaCl dissolved in 4kg water.
I have overlooked C) as possible 0.25mol NaCl in 1kg water as being a little too obvious.
PH stands for potential hydrogen.
pH can be accurately tested using acid-based indicators since it is a part of the pH of something itself. (acid and bases) The indicators themselves work when the acidic properties of the indicator begins to dissolve and form ions which gives the color indicating the pH.
Answer:
Explanation:
To solve problems like this, the very first thing to do is to write out the balanced equation for the process. The reaction is
Zn(s) + HCl(aq) → ZnCl2(aq) + H2(g)
and the balanced equation is
Zn(s) + 2 HCl(aq) → ZnCl2(aq) + H2(g)
So, by examining the stoichiometry, you can see that for every mole of Zn, two moles of HCl will be required. In turn, we need to know the number of moles of Zn is represented by 10.4 g. The molecular weight of Zn is 65.38 g/mol so
moles of Zn = 10.4 g/65.38 g/mol = 0.159 moles
and, twice as many moles of HCl is required so
# of moles of HCl required = 2 * 0.159 = 0.318 moles
Answer:
6.6253*10²¹molecules of ethane (C₂H₆) are present in 0.334 g of C₂H₆
Explanation:
Avogadro's Number is the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of that substance. Its value is 6.023 * 10²³ particles per mole. Avogadro's number applies to any substance.
In this case, being:
the molar mass of ethane C₂H₆ is:
C₂H₆: 2*12 g/mole + 6* 1 g/mole= 30 g/mole
Then you can apply the following rule of three: if 30 grams of C₂H₆ are present in 1 mole, 0.334 grams of C₂H₆ in how many moles are present?
moles of C₂H₆=0.011
Finally, taking into account the definition of Avogadro's number, you can apply the following rule of three: if there are 6.023 * 10²³ molecules of C₂H₆ in 1 mole, how many molecules are there in 0.011 moles?
molecules of C₂H₆= 6.6253*10²¹
<u><em>6.6253*10²¹molecules of ethane (C₂H₆) are present in 0.334 g of C₂H₆</em></u>
