Answer:
=B5/10
=E10
Explanation:
The above two formulas are the correct options. Remember for a valid formula in Excel, we must have the = sign first, and this should be followed by a valid formula. Saying that C5 should be E10 by writing =E10 at C5 is a formula certainly. And storing B5/10 at C5, through =B5/10 is also a valid formula. Hence, two formula out of four, and as mentioned above are the correct ones.
Answer:
You need to install Windows 7 over an existing version of Windows.
Explanation:
Brainiest??
Hi!
Well, this isn't exactly a question - but rather just a request. However, I'm going to attempt to try and <em>describe </em>to you how to approach this problem, instead of just writing the code for you and sending you on your way.
So, what's our general base goal here? We want to take a string into a function, and then print it out backwards. Seems simple enough!
Right away, we already have an idea how to set this code up. We need a main method which will call <em>PrintBackwards(), </em>which will have to take a parameter of type string.
This would look something like <em>PrintBackwards(string baseString). </em>Inside this method, we'd have to do something so we can see each character in this string and then store it in a new string.
I encourage you to try and tackle this on your own, but I can give you an idea. We can have a new valueless variable called reversedString, which will store our baseString but backwards.
We could try looping through the baseString for each character it possesses, and then keep adding onto our reversedString by doing something like +=. What I mean, is we'd access the very last index of baseString, and then keep appending characters into it.
So our loop would look something like <em>for(int i = baseString.length; i > 0; i--) {}.
</em>I haven't used C++ in awhile, so you'll have to find the specific syntax requirements. But with that loop, i represents the index of each character in baseString. It starts with the last index, and keeps going down in reverse.
<em>
</em>Inside our loop, we could do something like reverseString += baseString.index(i); Again, I don't remember the specific syntax - so you'll have to do this on your own.
<em>
</em>Hopefully, this helps! =)<em>
</em>
Answer:
Two disks RAID 1 and four disks RAID 5.
Explanation:
The RAID level stands for Redundancy array of independent disk drive level. It is a process whereby disk storage like hard disk drive or solid state disk are connected in array to function in parallel to each other, to promote performance and reliability. The categories of raid level are 0, 1, 3, 5, 10 etc.
The RAID level 1 writes data on both main disk and mirror disk. It is more efficient with only two disk. The RAID 5 strips data across disk array and stores a parity check on them. It can hold 16 disks efficient and can be used in the two channel RAID to hold the remaining four disks.
Answer:
from functools import reduce
def prod_all(*args):
prod = reduce(lambda x,y: x *y, args)
return prod
result = prod_all(4,6,8)
print(result)
Explanation:
The use of the "*args" passes a tuple of variable length to a python defined function. The function above takes any number of arguments and returns the product using the python reduce module and the lambda function.
