The probability of choosing a number that is not a multiple of 2 is P = 0.44
<h3 /><h3>How to find the probability?</h3>
We need to count the number of options for each digit.
- For the first digit, we have 8 options {1, 2, 3, 4, 5, 6, 7, 8}
- For the second digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}
- For the third digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}.
The total number of combinations is the product between the numbers of options:
C = 8*9*9 = 648
If we want our number to not be a multiple of 2 then it must end in a odd digit, the combinations that meet that condition are:
- For the first digit, we have 8 options {1, 2, 3, 4, 5, 6, 7, 8}
- For the second digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}
- For the third digit, we have 4 options {1, 3, 5, 7}.
C = 8*9*4 = 288
Then the probability of selecting a 3 digit number that is not a multiple of 2 is:
P = 288/648 = 0.44
If you want to learn more about probability, you can read:
brainly.com/question/251701
Answer:
iacbsc kakwc s s k kd sdidv d lm vdfj
Step-by-step explanation:
Answer:
A/B O.5 (you put 0.5 as A and B) but 0.5 is the answer.
Step-by-step explanation:
In expanded form of decimal fractions we will learn how to read and write the decimal numbers. ... (i) 100 + 0.5 + 0.06 + 0.008 (ii) 80 + 1 + 0.02 + 0.005.
Exponential growth has the form:
F=Ir^t, F=final amount, I=initial amount, r=rate, t=time.
First let's solve for the rate, r, using the points provided...
37325/34560=(Ir^2)/(Ir^1)
r≈1.08
Now find the initial amount...
34560=I(1.08)^1
I=32000 so now we have the entire equation, using x and y...
y=32000(1.08)^x
