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Minchanka [31]
3 years ago
14

Decimals numbers tenths​

Mathematics
1 answer:
sasho [114]3 years ago
5 0

Answer:

Example for that would be if you got 12.11 then the tenth decimal place would be 12.1

Hope this helps

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Of flowers in a field 43% are yellow . The others are white. A bee randombly lands on a flowerdescribe the complelment of the be
Dima020 [189]

Answer:

0.43

Step-by-step explanation:

Yellow flowers are 43%.

White flowers are = (100% - 43% ) = 57%

Consider there are total 100 flowers in the garden , so yellow ones are 43 and white ones are 57

Probability of a bee landing on a yellow flower is 43 out of 100

= 43/ 100

=0.43

4 0
3 years ago
The graph below shows three functions: Graph of function f of x equals 0.5 to the power x. Graph of function g of x is a line se
Phantasy [73]

Answer:   f(x)= 0.5^x has all real value as its domain.

Explanation: since, we have three functions f(x)=0.5^x,

while g(x) and p(x) are line segments.

Now, g(x) is a function by a line segment which passes through two points (-1.8,-3) and ( 1,3.8).

Thus it is clear that its domain will be the ends points. so domain of the function g(x) will be [-1.8, 3.8] which is the subset of real numbers set (R).

Similarly, domain of function p(x) will be [1.7, 1], which is also the subset of R.

But, when we talk about f(x) it contains all the possible value of x. Thus we can say that f(x)= 0.5^x has R as its domain.

8 0
3 years ago
Read 2 more answers
What is the radius of a circle with circumference 56 in?
Mnenie [13.5K]

the radius is 8.917197452 in

7 0
3 years ago
Compare the values of each 3 in the number 633,248
ipn [44]
633,248.
The difference of each 3 is that they have different place values.
The 3 on the right side is int he 1000s (thousands) place, and the 3 on the left is in the 10,000s (ten thousands) place. :) 

The one in the 10,000s place is 10 times larger than the one in the 1,000s place!
6 0
3 years ago
Solve the following system of equations: −2x + y = 1 −4x + y = −1
Katyanochek1 [597]

Answer:

<h2>x = 1, y = 3 → (1, 3)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}-2x+y=1\\-4x+y=-1&\text{change the signs}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-2x+y=1\\4x-y=1\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad2x=2\qquad\text{divide both sides by 2}\\.\qquad x=1\\\\\text{Put it to the first equation:}\\\\-2(1)+y=1\\-2+y=1\qquad\text{add 2 to both sides}\\y=3

5 0
3 years ago
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