Calculate the distance between points (0,0) and (4, 6) on the coordinate plane.

Johnny went to an apple farm to pick some apples. The admission to get in was $5.00 and the apples cost $0.75 per pound.

sasho [114]

Answer:

y=0.75x+5

Step-by-step explanation:

It would be this equation because you start at 5, which is the y-intercept, then you add 0.75 for every pound of apples. So on a graph you would start at 5 on the y-line then go up by 0.75

6 0

3 years ago

5x + 2x + 2 = 9x + 4

bija089 [108]

Step-by-step explanation:

Given

5x + 2x + 2 = 9x + 4

9x - 5x - 2x = 2 - 4

9x - 7x = - 2

2x = - 2

x = - 2 / 2

Therefore x = -1.

5 0

3 years ago

Read 2 more answers

How would I find the value of X in this equation

slava [35]

Sum of angles In all triangles are 180....line DAC is horizontal and therefore is 180 degrees ....so minus 180 degrees from 105 and you get 75 degrees....and since the sum of all angles in a triangle is 180...add 75 and 67 which would be 142 degrees ...then minus 142 from 180 degrees to get 38 degrees for x

4 0

3 years ago

Write an equation for the circle with endpoints of a diameter (9, 4) and (-3, -2)

inysia [295]

If the diameter is at (9,4) and (-3,-2), then the center of the circle is the midpoint of that segment.

and since we know that the radius of a circle is half of the diameter, whatever long that diameter segment is, the radius is half that.

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 9 &,& 4~) 
% (c,d)
&&(~ -3 &,& -2~)
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{ x_2 + x_1}{2}\quad ,\quad \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{-3+9}{2}~~,~~\cfrac{-2+4}{2} \right)\implies \stackrel{center}{(3~,~1)}$

$\bf -------------------------------\\\\
~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 9 &,& 4~) 
% (c,d)
&&(~ -3 &,& -2~)
\end{array}
\\\\\\
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
d=\sqrt{(-3-9)^2+(-2-4)^2}\implies d=\sqrt{(-12)^2+(-6)^2}
\\\\\\
d=\sqrt{180}\qquad \qquad \qquad radius=\cfrac{\sqrt{180}}{2}$

$\bf -------------------------------\\\\
\textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{3}{ h},\stackrel{1}{ k})\qquad \qquad 
radius=\stackrel{\frac{\sqrt{180}}{2}}{ r}
\\\\\\
(x-3)^2+(y-1)^2=\left( \frac{\sqrt{180}}{2} \right)^2\implies (x-3)^2+(y-1)^2=\cfrac{(\sqrt{180})^2}{2^2}
\\\\\\
(x-3)^2+(y-1)^2=\cfrac{180}{4}\implies (x-3)^2+(y-1)^2=45$

7 0

3 years ago

Right the slope intercept form of the equation of of each line

Burka [1]

Answer:

Slope intercept form is y=mx+b

So y=-1/2x(m=slope which you go down one over 2 from your y-intercept)

y=-1/2x ( There would be no b because your b is 0, that's where it crosses the y axis)

Step-by-step explanation:

6 0

3 years ago

Calculate the distance between points (0,0) and (4, 6) on the coordinate plane.​

Calculate the distance between points (0,0) and (4, 6) on the coordinate plane.