<u>Explanation</u><u>:</u>
Consider ABCD is a rhombus
We know that
All sides are equal in rhombus i.e,
⇛AB=BC=CD=DA
and AC and BD are digonals
Given that
Diagonal and the side of the rhombus are equal.
⇛AB = BC = CD = DA = AC
Diagonal AC divides the rhombus into two triangles .
They are ∆ BAC and ∆ DAC
In triangle BAC
BA=BC=AC,(Given)
⇛∠ BAC=∠ABC= ∠ACB =60°→→→Eqn(i)
Similarly in ∆DAC ,
DA=DC=AC
⇛∠DAC=∠ACD=∠ADC=60°→→→Eqn(ii)
From eqn(i) and eqn(ii)
∠A=∠BAC+∠DAC=60°+60°=120°
and
∠B= ∠ABC = 60°.
and
∠C=∠ACB+∠ACD=60°+60°=120°
and
∠D =∠ADC=60°
∴ ∠A = 120° , ∠B = 60° ,∠C = 120° & ∠D = 60°
<u>Answer:</u><u>-</u>The measures of the all angles in the rhombus are 120° , 60° ,120° and 60°.
Note: [Figure refers in the attached file.
Answer:
d c a
Step-by-step explanation:
Answer:
A) −3(x3+2x−1)
Step-by-step explanation:
Factor 3-3x^3-6x to get −3(x3+2x−1)
Answer:
It will take 0.75B hours for the return leg
Step-by-step explanation:
Here, given that the first leg of the trip was for B hours at 3 miles per hour , we want to calculate the number of hours the return leg will take at 4 miles per hour given that it is the same distance.
Mathematically, we know that ;
Distance = speed * time
So the distance taken on the first leg of the trip would be;
Distance = 3 miles per hour * B hours = 3B miles
Now, this distance was traveled on the return leg also.
This means that the time taken here will be;
Time on return leg = distance/speed = 3B/4 = 0.75B hours
