Answer:
4 in approx
Step-by-step explanation:
Step one:
given data
circle with 25 inch circumference
c= 25in
Required:
the radius of the circle
Step two:
the expression for the circumference of a circle is
C= 2πr
making r the subject of the formula we have
r= c/2π
r= 25/2*3.142
r= 25/6.284
r=3.97
r=4 in approx
Your answer is gonna be D. 100%
Answer:
Step-by-step explanation:
Well, if you do 1 times any number then it will still be that number.
so the number of ones that you can take from 17 is well, 17.
Hope this helps!
Answer:
∠B ≅ ∠F ⇒ proved down
Step-by-step explanation:
<em>In the </em><em>two right triangles</em><em>, if the </em><em>hypotenuse and leg</em><em> of the </em><em>1st right Δ ≅</em><em> the </em><em>hypotenuse and leg</em><em> of the </em><em>2nd right Δ</em><em>, then the </em><em>two triangles are congruent</em>
Let us use this fact to solve the question
→ In Δs BCD and FED
∵ ∠C and ∠E are right angles
∴ Δs BCD and FED are right triangles ⇒ (1)
∵ D is the mid-point of CE
→ That means point D divides CE into 2 equal parts CD and ED
∴ CD = ED ⇒ (2) legs
∵ BD and DF are the opposite sides to the right angles
∴ BD and DF are the hypotenuses of the triangles
∵ BD ≅ FD ⇒ (3) hypotenuses
→ From (1), (2), (3), and the fact above
∴ Δ BCD ≅ ΔFED ⇒ by HL postulate of congruency
→ As a result of congruency
∴ BC ≅ FE
∴ ∠BDC ≅ ∠FDE
∴ ∠B ≅ ∠F ⇒ proved
