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Ksivusya [100]
3 years ago
9

Last year Rikki sang 960 songs with his rock band. How many songs did he sing per month? How did you get your answer?

Mathematics
1 answer:
alexira [117]3 years ago
6 0
If he sang the same number of songs each month, he sang 80 songs per month.

960/12 (months) = 80 (songs per month)
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In order to make a service for four 1 3/4 cups of chopped vegetables are needed. Based on this information, determine the amount
Mila [183]

For this case we propose a rule of three according to the data of the statement. To do this, we convert the mixed number into an improper fraction:

1 \frac {3} {4} = \frac {4 * 1 + 3} {4} = \frac {7} {4}cups

4 ----------> \frac {7} {4}

10 ----------> x

Where the variable "x" represents the amount of chopped of vegetables needed for 10 people.

x = \frac {10 * \frac {7} {4}} {4}\\x = \frac {\frac {70} {4}} {4}\\x = \frac {70} {16}\\x = \frac {35} {8}

This is equivalent to 4 \frac {3} {8}cups.

Answer:

4 \frac {3} {8} cups

6 0
3 years ago
8) Shawna had $20 to spend on six pencils. After buying them she had
Brums [2.3K]

It cost 2 dollers each.

3 0
3 years ago
Write 6.005 in expanded form
jenyasd209 [6]

Answer:

6+0.005

Step-by-step explanation:

8 0
3 years ago
A design engineer wants to construct a sample mean chart for controlling the service life of a halogen headlamp his company prod
tekilochka [14]

Answer:

C) 515 hours.

D) 500 hours

c) sample 3

Step-by-step explanation:

1. Sample 2 mean = x2`= ∑x2/n2= 2060/4= 515 hours

Sample Service Life (hours)

1                2              3

495      525            470

500         515           480

505        505            460

<u>500         515             470        </u>

<u>∑2000     2060         1880</u>

x1`= ∑x1/n1= 2000/4= 500 hours

x2`= ∑x2/n2= 2060/4= 515 hours

x3`= ∑x3/n3= 1880/4=  470 hours

2. The mean of the sampling distribution of sample means for whenever service life is in control is 500 hours . It is the given mean in the question and the limits are determined by using  μ ± σ , μ±2 σ  or μ ± 3 σ.

In this question the limits are determined by using  μ ± σ .

3. Upper control limit = UCL = 520 hours

Lower Control Limit= LCL = 480 Hours

Sample 1 mean = x1`= ∑x1/n1= 2000/4= 500 hours

Sample 2 mean = x2`= ∑x2/n2= 2060/4= 515 hours

Sample 3 mean = x3`= ∑x3/n3= 1880/4=  470 hours

This means that the sample mean must lie within the range 480-520 hours but sample 3 has a mean of 470 which is out of the given limit.

We see that the sample 3 mean is lower than the LCL. The other  two means are within the given UCL and LCL.

This can be shown by the diagram.

8 0
2 years ago
What is the length of the hypotenuse in the following figure.
xeze [42]

Answer:

5

Step-by-step explanation:

what do you mean ?? its already written there

8 0
2 years ago
Read 2 more answers
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