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Assoli18 [71]
3 years ago
13

A student claims that the rectangular point below can be represented by the

Mathematics
1 answer:
Sladkaya [172]3 years ago
3 0

Since we don't have a figure we'll assume one of them is right and we're just being asked to check if they're the same number.  I like writing polar coordinates with a P in front to remind me.

It's surely false if that's really a 3π/7; I'll guess that's a typo that's really 3π/4.

P(6√2, 7π/4) = ( 6√2 cos 7π/4, 6√2 sin 7π/4 )

P(-6√2, 3π/4) = ( -6√2 cos 3π/4, -6√2 sin 3π/4 )

That's true since when we add pi to an angle it negates both the sine and the cosine,

cos(7π/4) = cos(π + 3π/4) = -cos(3π/4)

sin(7π/4) = sin(π + 3π/4) = -sin(3π/4)

Answer: TRUE

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Nojo is 5 years older then jacob . the product of their ages is 84 . now old is noj
mixer [17]
We can make two simple equations to express their ages to each other, then solve for one of the variables. Let n be Nojo's age and j be Jacob's age.

n(j) = 84
n - 5 = j
Use substitution to get only one variable in an equation.

n (n - 5) = 84
n^2 - 5n = 84

Since we have n to the power of 2, this equation has two possible answers, but since we are given four possible answer, just substitute them in the equation until one makes the left side equal 84.

<span>n^2 - 5n = 84
</span>12^2 - 5 (12) = 84
144 - 60 = 84
84 = 84

The answer is C = 12
5 0
3 years ago
1/6 minus 1/10 simplifiy
andriy [413]
1/6 -1/10 
= 10/60 - 6/60
= 4/60
= 1/15
6 0
3 years ago
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PLEASE HELP 2O POINTS
vovangra [49]
C. The first is a solution, but the second is not.

5x - y/3 = 13 ; (2,-9)
substitute the letters:
5(2) - (-9/3) = 13 
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10 + 3 = 13 ;
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5x - y/3 = 13 ; (3,-6)
5(3) - (-6/3) = 13
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hope i could help
4 0
3 years ago
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What is the measure of Zx?
MA_775_DIABLO [31]

Answer:

x = 139º

Step-by-step explanation:

A line = 180º

180º - 41 º = 139º

3 0
2 years ago
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Solve for x in terms of r, s and t : s=2x+t/r
Anna007 [38]

For this case we have the following equation:

s = \frac {2x + t} {r}

We must clear the value of the variable "x" as a function of r, s and t:

If we multiply by "r" on both sides of the equation we have:

rs =2x + t

If we subtract "t" on both sides of the equation we have:

rs-t = 2x

If we divide by "2" on both sides of the equation we have:

x = \frac {rs-t} {2}

Thus, the value of the variable "x" is:

x = \frac {rs-t} {2}

Answer:

x = \frac {rs-t} {2}

4 0
3 years ago
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