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Savatey [412]
3 years ago
10

Please someone help me quick!!!! It's about Domain and range, Please! Anyone!

Mathematics
1 answer:
BARSIC [14]3 years ago
8 0

Answer:

Step-by-step explanation:

They already said the domain of f(x) is x≥0.

The smallest value of f(x) is f(0) = 9.

Range of f(x) is y≥9.

The radicand of a square root must be non-negative, so the domain of f⁻¹(x) is x≥9.

The range is y≥0.

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If f(x) = 2x - 4 and g(x)= -5x + 6, then what is f(g(x))?
Nikitich [7]

Answer:

B. f(g(x)) = -10x + 8

Step-by-step explanation:

When evaluating f(g(x)), substitute what g(x) is in place of g(x).

So instead of

f(g(x))

the function would be:

f(-5x + 6).

Now all you have to do is evaluate this.

To evaluate this function, substitute the value inside the f(x) for all instances of x in the equation.

f(x) = 2x - 4

f(-5x + 6) = 2(-5x + 6) - 4

f(-5x + 6) = -10x + 12 - 4

f(-5x + 6) = -10x + 8

Therefore, f(g(x)) = -10x + 8.

5 0
3 years ago
PLEASE HELP QUICK!! (25 Points) Name the postulate or theorem you can use to prove the triangles congruent.
Akimi4 [234]
Hello!

You know that two sides and one of the angles are congruent

The only choice that has two sides and 1 angle is ASA postulate

The answer is ASA postulate

Hope this helps!
7 0
4 years ago
Read 2 more answers
Math question screen shot down below
frozen [14]

Answer:

Try B i think it might be B

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
PLS HELP ME
IgorLugansk [536]

Answer :

Option B

Step by step explanation :

As we can see in figure, Triangle is right angled at A

In ∆ABC

By Pythagoras theorem,

BC² = AC² + AB²

=> BC² = (3)² + (4)²

=> BC² = 9 + 16

=> BC² = 25

=> BC = 5 cm

We know,

\:\mathsf{Area \:of\: triangle}=\:\mathsf{\frac{1}{2}\: x\: base\: x\: height}

Here,

base = AC = 3cm

height = AB = 4cm

=> \:\mathsf{Area \:of\: triangle}=\:\mathsf{\frac{1}{2} \:x\: 3cm\: x\:4cm}

=> \:\mathsf{Area \:of\: triangle\: = \:3cm\: x\: 2cm}

=> \:\bf\boxed{Area \:of\: triangle\: = \:6cm²}

As BC = DE

And then BD = EC

it shows the property of rectangle

So BD = 6 cm

Now,

\:\mathsf{Area \:of\: rectangle\: =\: length \:x\: width}

=> Area of rectangle = 6cm x 5cm

=> \:\bf\boxed{Area\: of\: rectangle\: = \:30cm²}

Now,

Area of the figure = Area of rectangle + Area of triangle

=> Area of the figure = 30cm² + 6cm²

=> \:\bf\boxed{Area\: of\: the\: figure\: = \:36cm²}

Therefore, <u>option B</u> is the correct answer for this question.

3 0
3 years ago
A cylinder has a diameter of 40 feet and a height of 32 feet. What is the surface area of the cylinder? Express the answer in te
givi [52]

Answer:

i think its 2,080

Step-by-step explanation:

the diameter is 40ft and the radius r=\frac{40}{2}=20ft and height is h=32ft.

A=2pi(20)(20+32)=40pi52=2,080pi square ft

3 0
4 years ago
Read 2 more answers
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