Answer:
$16
Step-by-step explanation:
Multiply $80 dollars by 20% or .2.
You should get $16.
A tip for the future is to move the decimal point to the left twice.
ie. 60%=0.6, 175%=1.75, 3%=0.03
( y - 4 ) ( y² + 4 y + 16 ) =
= y³ + 4 y² + 16 y - 4 y² - 16 y - 64 = y³ - 64
If the result is the polynomial of the form:
y³ + 4 y² + a y - 4 y² - a y - 64
a = 16
Answer:
well if we take -12 and divide it by four we will get -3.
Step-by-step explanation:
If we have a total of negative 12, just divide it by 4 and the difference between each division is the sum.
Your answer will be -3 on the number line.
:)
Remember that the radicand (the area under the root sign) must be positive or zero for a radical with an even index (like the square root or fourth root, for example). This is because two numbers squared or to the fourth power, etc. cannot be negative, so there are no real solutions when the radicand is negative. We must restrict the domain of the square-root function.
If the domain has already been restricted to
, we can work backwards to add 11 to both sides. We see that
must be under the radicand, so the answer is
A.
a.
The polynomial w^2+18w+84 cannot be factored
The perfect square trinomial is w^2+18w + 81
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The reason the original can't be factored is that solving w^2+18w+84=0 leads to no real solutions. Use the quadratic formula to see this. The graph of y = x^2+18x+84 shows there are no x intercepts. A solution and an x intercept are basically the same. The x intercept visually represents the solution.
w^2+18w+81 factors to (w+9)^2 which is the same as (w+9)(w+9). We can note that w^2+18w+81 is in the form a^2+2ab+b^2 with a = w and b = 9
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b.
The polynomial y^2-10y+23 cannot be factored
The perfect square trinomial is y^2-10y + 25
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Using the quadratic formula, y^2-10y+23 = 0 has no rational solutions. The two irrational solutions mean that we can't factor over the rationals. Put another way, there are no two whole numbers such that they multiply to 23 and add to -10 at the same time.
If we want to complete the square for y^2-10y, we take half of the -10 to get -5, then square this to get 25. Therefore, y^2-10y+25 is a perfect square and it factors to (y-5)^2 or (y-5)(y-5)
