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3 years ago

(3) GEOMETRY IMAGE BELOW. 20 POINTS!!

Mathematics

2 answers:

Levart [38]3 years ago

5 0

Answer:

option D

Step-by-step explanation:

option D is the correct answer of this question.

the length of the mid segment was 42 option A

( previous question ) according to me and it is right so please recheck your previous answer as it was option A not D

hope this will be helpful to you.

and mark my answer as brainlist plzzzz.

Vinvika [58]3 years ago

4 0

The answer above is correct it’s option D

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NEED HELP ASAP PLEASE

IrinaVladis [17]

Z would also be 63 degrees. Triangle WXZ is isosceles, as sides WX and WZ are marked as congruent. This means that the two base angles of the triangle (the bottom two) are congruent. You already know that one of the base angles, X (or WXY), is 63 degrees, so using this reasoning, the other base angle, YZW, is 63 degrees as well. I hope this helps!

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3 years ago

There are 407 students who are enrolled in an introductory Chinese course if there are five boys to every 6 girls how many boys

Mrac [35]

Answer:

6x+5x=407

11x=407

x=37

boys

Step-by-step explanation:

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3 years ago

A car travels 15 miles per gallon of

Arlecino [84]

Answer:

15x = y

Step-by-step explanation:

15 times the gallons of gas = miles

15x = y

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3 years ago

Of 1,050 randomly selected adults, 360 identified themselves as manual laborers, 280 identified themselves as non-manual wage ea

garik1379 [7]

Answer:

We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.

Step-by-step explanation:

We have a sample of executives, of size n=160, and the proportion that prefer trucks is 26%.

We have to calculate a 95% confidence interval for the proportion.

The sample proportion is p=0.26.

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.26*0.74}{160}}\\\\\\ \sigma_p=\sqrt{0.0012}=0.0347$

The critical z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

$MOE=z\cdot \sigma_p=1.96 \cdot 0.0347=0.068$

Then, the lower and upper bounds of the confidence interval are:

$LL=p-z \cdot \sigma_p = 0.26-0.068=0.192\\\\UL=p+z \cdot \sigma_p = 0.26+0.068=0.328$

The 95% confidence interval for the population proportion is (0.192, 0.328).

We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.

3 0

3 years ago

A.)0.406 B.)0.435 C.)0.303 D.)0.154

Serggg [28]

I think it should be option d

3 0

3 years ago