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1 year ago

What is the system of inequalities associated with the following graph?

Mathematics

1 answer:

GarryVolchara [31]1 year ago

3 0

Answer: C

Step-by-step explanation:

$y=-2$ is dotted and shaded below, so it represents $y < -2$ .

Also, $x+y=1$ is shaded above, so it represents $x+y < 1$ .

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Part A

alexgriva [62]

Answer:

6=2 , 12=4, 15=5, 24=8

Step-by-step explanation:

6 0

3 years ago

2,3,5,9,17,33 what are the next three terms?

stich3 [128]

The next three terms of sequence are 65, 129 and 257

Solution:

Given sequence is:

2, 3, 5, 9, 17, 33

We have to find the next three terms in sequence

Let us find the logic used in this sequence

$2 + 2^0 = 2 + 1 = 3\\\\3 + 2^1 = 3 + 2 = 5\\\\5 + 2^2 = 5 + 4 = 9\\\\9 + 2^3 = 9 + 8 = 17\\\\17 + 2^4 = 17 + 16 = 33$

Thus the sequence is increasing by 2 raised to power 0, 1, 2 and so on

Thus the next three terms are found by:

$33 + 2^5 =33 + 32= 65\\\\65 + 2^6 = 65 + 64 = 129\\\\129 + 2^7 = 129 + 128 = 257$

Thus the next three terms of sequence are 65, 129 and 257

3 0

2 years ago

Geoff charges 27$ for 3 hours of swimming lessons

igor_vitrenko [27]

Answer: 27/3=9 which means 9$ per hour

32/4=8 which means 8$ per hour

Step-by-step explanation:

Answers is annie deal is the best

6 0

2 years ago

Read 2 more answers

Original price 65.00; Markdown: 12%

Murrr4er [49]

Muliply 65 and 0.12 and get 7.8

Subtract 65-7.8 to get marked down price

57.2 is the price after markdown

6 0

3 years ago

Help pleaseeeeeeeeeeeeeeeeeeeeeee

bixtya [17]

Answer: $\bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}$

Step-by-step explanation:

(1) (12, 18, 27, ...)

The common ratio is:

$r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\ r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}$

$(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\ r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}$

3 0

2 years ago