Answer:
The proportion of students whose height are lower than Darnell's height is 71.57%
Step-by-step explanation:
The complete question is:
A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 centimeters. Darnel is a middle school student with a height of 161.4cm.
What proportion of proportion of students height are lower than Darnell's height.
Answer:
We first calculate the z-score corresponding to Darnell's height using:
We substitute x=161.4 , , and to get:
From the normal distribution table, we read 0.5 under 7.
The corresponding area is 0.7157
Therefore the proportion of students whose height are lower than Darnell's height is 71.57%
Kinetic engery = -1/2mv^2
Work = Fd
Combine:
-1/2mv^2 - Fd = 0
-1/2mv^2 = (0.30*15000*9.81*cos(6))d = 0
Multiply both sides by 2:
v^2 = 2d(0.30*9.81*cos(6))
Solve for d:
d=v^2 / 2(0.30*9.81*cos96))
v = speed:
d = 35^2 / 2*0.30 * 9.81 * cos(6)
d = 1225 / 5.85376
d = 209.27 meters. Round answer as needed.
Answer:
WHAT IS YOUR QUESTION
Step-by-step explanation:
Answer:
5. D 6. B 7. A
Step-by-step explanation:
it is just like a square all sides are the same