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agasfer [191]
3 years ago
15

Prob(Total time in process > t) = EXP(-t/T) T = (1/(Rp - Ri)) = (1 / Rs) R = min(Ri, Rp) u=R/Rp Dominic runs an appliance rep

air shop and sells replacement parts for appliances to walk in customers. Customer take an average of 5 minutes. It is a single phase system with 1 server. The coefficient of arrivals and the coefficient of processing times is 1.0. If Dominic's utilization were 80%, how many would be standing in line waiting to be served?
Business
1 answer:
bija089 [108]3 years ago
4 0

Answer:

3.20 customers

Explanation:

If one customer takes 5 minutes then in 1 hour =

60/5 = 12 minutes

This is the service rate

Utilization = arrival rate divided by service rate

0.80 = AR / 12

AR = 0.89x12

Arrival rate = 9.6/hour

We get average of those waiting in system

AR/SR-AR

= 9.6/(12-9.6)

9.6/2.4

= 4

4 x 0.80 = 3.2 this is the average of those waiting in line

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Answer and Explanation:

Given that

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3 0
3 years ago
The price of cigars is $10, with a quantity demanded of 1,000 per day. If the price increases to $12, the quantity demanded decl
saveliy_v [14]

Answer:

PED = - 1

Explanation:

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PED = [(800 - 1000) / 1000]  /  [(12 - 10) / 10]

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8 0
3 years ago
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oksian1 [2.3K]

Answer and Explanation:

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Andreas93 [3]

Answer:

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Hope this helps!!
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