Answer:
49.865%
Step-by-step explanation:
Given that:
μ = 4 ; σ = 1
For x = 4
P(x < 4) :
Z score (x - μ) / σ
P(x < 7) - P(x < 4)
((7 - 4) / 1) - ((4 - 4) / 1)
P(Z < 3) - P(Z < 0)
Usibg the Z probability calculator :
0.99865 - 0.5
= 0.49865
= 0.49865 * 100
= 49.865%
9/27, 12/27, 16/27
So this is a geometric sequence as each term is 4/3 the previous term.
Since the common ration is greater than one the sum of the series diverges, it does not exist. (The sum just keeps getting larger and larger)
For a geometric series to have a sum r^2<1
So that the normal sum....
s(n)=a(1-r^n)/(1-r) becomes if r^2<1
s=a/(1-r)
Answer: 2526 dollars
=============================
Work Shown:
Plug n = 400,000 into the function and simplify
f(n) = 939 + 5.29*(n-100,000)/(1,000)
f(400,000) = 939 + 5.29*(400,000-100,000)/(1,000)
f(400,000) = 939 + 5.29*(300,000)/(1,000)
f(400,000) = 939 + 5.29*(300)
f(400,000) = 939 + 1,587
f(400,000) = 2526
260 because the tens position is the far right one before the decimal, and the number is above 5.
Number of boys in the gym class = 12
Number of girls in the gym class = 10
then
Ratio of boys to ratio of girls = 12:10
= 6:5
Now
Number of boys joining the gym class later = 6
So after the new boys join the number of boys in the gym class becomes = 18
The ratio of boys to girls have to remain the same
Let us assume that the number of girls that need to join the gym class = x
Then
6/5 = 18/(x + 10)
6(x + 10) = 18 * 5
6x + 60 = 90
6x = 90 - 60
6x = 30
x = 30/6
= 5
So the number of girls that need to join the gym class to keep the ratio same is 5. I hope the procedure is clear enough for you to understand.
