PLZ I REALLY NEED HELP Find the values of x and y in parallelogram PQRS
1 answer:
Answer:
x = 5 and y = 7
Step-by-step explanation:
Given that,
PT = x+2, TR=y, QT=2x, TS=y+3
We need to find the value of x and y.
The diagonal of a parallelogram bisect each other. It means,
PT = TR and QT = TS
ATQ,
y = x+2 ...(1)
and
y+3 = 2x ....(2)
Subtracting equation (1) and (2).
y-(y+3) = x+2-2x
y-y-3 = 2-x
-3 = 2-x
x = 2+3
x = 5
Put the value of x in equation (1).
y = 5 + 2
y = 7
Hence, the values of x and y are x = 5 and y = 7.
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