PLZ I REALLY NEED HELP Find the values of x and y in parallelogram PQRS
1 answer:
Answer:
x = 5 and y = 7
Step-by-step explanation:
Given that,
PT = x+2, TR=y, QT=2x, TS=y+3
We need to find the value of x and y.
The diagonal of a parallelogram bisect each other. It means,
PT = TR and QT = TS
ATQ,
y = x+2 ...(1)
and
y+3 = 2x ....(2)
Subtracting equation (1) and (2).
y-(y+3) = x+2-2x
y-y-3 = 2-x
-3 = 2-x
x = 2+3
x = 5
Put the value of x in equation (1).
y = 5 + 2
y = 7
Hence, the values of x and y are x = 5 and y = 7.
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<h2>~<u>Solution</u> :-</h2>
Here, it is given that the bag contains 25 paise coins and 50 paise coins in which, 25 paise coins are 6 times than that of 50 paise coins. Also, the total money in the bag is Rs. 6.
- Hence, we can see that, here, we have been given the linear equation be;
Let the number of coins of 50 paise will be $ x $ and the number of coins of 25 paise will be $ 6x $ as given. . .
Hence,
- Hence, the number of 50 paise coins will be <u>2</u>. And, 6 times of two be;
- Hence, the number of 25 paise coins will be <u>12</u>.