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SCORPION-xisa [38]
3 years ago
12

5208 divided by 4 in long division

Mathematics
1 answer:
Veronika [31]3 years ago
4 0

Answer:

 1 3 0 2

4 5 2 0 8

− 4      

 1 2    

− 1 2    

   0 0  

 −   0  

     0 8

   −   8

       0

Step-by-step explanation:


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Helen plays basketball. For free throws, she makes the shot 75% of the time. Helen must now attempt two free throws. The probabi
CaHeK987 [17]

Answer: 0.6375

Step-by-step explanation:

Let's assume that the event that she'll make the first shot is given as P(A) while making the second shot is P(B). Therefore, P(A/B) = 0.85

Therefore, the probability that she makes both free throws will be denoted as:

= 0.75 × 0.85

= 0.6375

3 0
3 years ago
In Exercises 40-43, for what value(s) of k, if any, will the systems have (a) no solution, (b) a unique solution, and (c) infini
svet-max [94.6K]

Answer:

If k = −1 then the system has no solutions.

If k = 2 then the system has infinitely many solutions.

The system cannot have unique solution.

Step-by-step explanation:

We have the following system of equations

x - 2y +3z = 2\\x + y + z = k\\2x - y + 4z = k^2

The augmented matrix is

\left[\begin{array}{cccc}1&-2&3&2\\1&1&1&k\\2&-1&4&k^2\end{array}\right]

The reduction of this matrix to row-echelon form is outlined below.

R_2\rightarrow R_2-R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\2&-1&4&k^2\end{array}\right]

R_3\rightarrow R_3-2R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&3&-2&k^2-4\end{array}\right]

R_3\rightarrow R_3-R_2

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&0&0&k^2-k-2\end{array}\right]

The last row determines, if there are solutions or not. To be consistent, we must have k such that

k^2-k-2=0

\left(k+1\right)\left(k-2\right)=0\\k=-1,\:k=2

Case k = −1:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-1-2\\0&0&0&(-1)^2-(-1)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-3\\0&0&0&-2\end{array}\right]

If k = −1 then the last equation becomes 0 = −2 which is impossible.Therefore, the system has no solutions.

Case k = 2:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&2-2\\0&0&0&(2)^2-(2)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&0\\0&0&0&0\end{array}\right]

This gives the infinite many solution.

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3 years ago
The table shows the distances and times that four rowboats traveled. Which rowboat was the fastest?
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Um where is the table at
 
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Who whats to talk <br> im here<br> .0.
Vsevolod [243]

Answer:

:( :( :(

Step-by-step explanation:

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today, 6 friends went out for lunch. their total Bill was $41.88, including tax and gratuity. they decide to split the Bill equa
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Each person will get back $3.02

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