$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{2}~,~\stackrel{y_1}{-5})\qquad B(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{6+2}{2}~~,~~\cfrac{1-5}{2} \right)\implies \left( \cfrac{8}{4}~,~\cfrac{-4}{2} \right)\implies (4,-2)$

7 0

2 years ago

How do you find the legs of a right triangle when only given the hypotenuse?

tangare [24]

Answer:

We know that a^2+b^2=c^2. The 45° angle lets us know that y=x (45+45+90=180), so the problem is y^2+x^2=4sqrt of 2

$4 \sqrt{2} = \sqrt{32 } \\ \sqrt{32} ^{2} = 32$

So you get y^2+x^2=32, and from there, since we know x and y are equal, you can just divide 32 by 2 then take the square root of that, so the answer should be 4 for both x and y

Step-by-step explanation:

let me know if I'm wrong lol

6 0

1 year ago

Tell me if this is right

vfiekz [6]

Answer:

what I'm bored

Step-by-step explanation:

what's u need help with anything I'

6 0

2 years ago