With a reflection across the y-axis followed by a translation of one unit to the right and three units up, and a dialation centered at the origin with a scale factor of 2
Answer:
His gain percent would have been 8%
Step-by-step explanation:
The key to answering this question is to first calculate the price at which the wheat flour was bought.
Mathematically;
% profit = (selling price-cost price)/cost price * 100%
Let the cost price be $x
Thus;
% profit = (30-x)/x * 100
20 = 100(30-x)/x
20x = 3000-100x
100x + 20x = 3000
120x = 3000
x = 3000/120
x = Rs 25
So let’s assume he sold at Rs 27
His profit would have been 27-25 = 2
His gain or loss percentage would’ve been;
2/25 * 100/1 = 200/25 = 8% (gain, since selling price is greater than the cost price)
a. Find the probability that an individual distance is
greater than 214.30 cm
We find for the value of z score using the formula:
z = (x – u) / s
z = (214.30 – 205) / 8.3
z = 1.12
Since we are looking for x > 214.30 cm, we use the
right tailed test to find for P at z = 1.12 from the tables:
P = 0.1314
b. Find the probability that the mean for 20 randomly
selected distances is greater than 202.80 cm
We find for the value of z score using the formula:
z = (x – u) / s
z = (202.80 – 205) / 8.3
z = -0.265
Since we are looking for x > 202.80 cm, we use the
right tailed test to find for P at z = -0.265 from the tables:
P = 0.6045
c. Why can the normal distribution be used in part (b),
even though the sample size does not exceed 30?
I believe this is because we are given the population
standard deviation sigma rather than the sample standard deviation. So we can
use the z test.
1st. 18m+9
2nd. 3(3+6m)
3rd. 9+18m
4th. 3(6m+3)
