Answer:
x = 1
y = 3
Step-by-step explanation:
2x + 1 = y ------- eqn (1)
2y = 6--------eqn (2)
from eqn(2)
2y = 6
y = 3
when you divide 6 by 2y
substitute y = 3 into eqn (1)
2x + 1 = y
2x + 1 = 3
2x = 3-1
2x = 2
therefore
x = 1
I think 7a^3b^6, but im not sure so im sorry if it is wrong
Answer:
D:) (2,2,) is the Answer
Step-by-step explanation:
Solve the following system:
{X - 2 Y = -2 | (equation 1)
{3 X - 2 Y = 2 | (equation 2)
Swap equation 1 with equation 2:
{3 X - 2 Y = 2 | (equation 1)
{X - 2 Y = -2 | (equation 2)
Subtract 1/3 × (equation 1) from equation 2:
{3 X - 2 Y = 2 | (equation 1)
{0 X - (4 Y)/3 = (-8)/3 | (equation 2)
Multiply equation 2 by -3/4:
{3 X - 2 Y = 2 | (equation 1)
{0 X+Y = 2 | (equation 2)
Add 2 × (equation 2) to equation 1:
{3 X+0 Y = 6 | (equation 1)
{0 X+Y = 2 | (equation 2)
Divide equation 1 by 3:
{X+0 Y = 2 | (equation 1)
{0 X+Y = 2 | (equation 2)
Collect results:
Answer: {X = 2 , Y = 2
Answer:
9 is answer . . . . . . . ........
