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3 years ago

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Ava bought 1/2 lb of candy. She is going to share the candy with 2 of her friends. If each of the 3 girls get the same amount, h

ow much will each girl receive?

1 answer:

dedylja [7]3 years ago

5 0

The three girls will receive 1/6 pound of candy each.

Step-by-step explanation: 1/2 divided by 3 = 1/6

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Kyle and his brother have a marble set. Of the marbles 12 are blue this represents 50/100of ALL the marbles. What decimal is equ

Alex73 [517]

To find this you would do 50/100 which equals .5

3 0

3 years ago

-x+4= 2x+1 equation steps

kykrilka [37]

-x + 4 = 2x + 1

add x to both sides

4 = 3x + 1

subtract 1 from both sides

3 = 3x

dived 3 from both sides

1 = x

4 0

3 years ago

Read 2 more answers

What is the m∠ACB in the circle shown below?

GuDViN [60]

Question:

What is the m∠ACB in the circle shown below?

Answer:

45

Step-by-step explanation:

So we know it is <u><em>less than a right angle</em></u> and it is not a obtuse angle it is less than 90 degrees. 45 is less, 90 is equal(<em>not what we are looking for</em>) , 120, is greater, and 180 is greater which leaves us to our answer 45.

4 0

3 years ago

Helllp geometry! Pls!

creativ13 [48]

He should use the Pythagorean Theorem to find the missing length.

Since KT is tangent to the circle and TL reaches the center of circle L, the measure of angle LTK is 90 degrees. This means that triangle LTK is a right triangle which means the Pythagorean Theorem can be used.

So,
TL²+(12)²=(13)²
=> TL²+144=169
=> TL²=25
=> TL = 5

Therefore, the radius of circle L is 5 feet.

7 0

3 years ago

How would you solve this? help.

Eddi Din [679]

Answer:

<em>Center: (3,3)</em>

<em>Radius: </em> $2\sqrt{5}$ <em />

Step-by-step explanation:

<u>Midpoint and Distance Between two Points</u>

Given two points A(x1,y1) and B(x2,y2), the midpoint M(xm,ym) between A and B has the following coordinates:

$\displaystyle x_m=\frac{x_1+x_2}{2}$

$\displaystyle y_m=\frac{y_1+y_2}{2}$

The distance between both points is given by:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Point (5,7) is the center of circle A, and point (1,-1) is the center of the circle B. Given both points belong to circle C, the center of C must be the midpoint from A to B:

$\displaystyle x_m=\frac{5+1}{2}=\frac{6}{2}=3$

$\displaystyle y_m=\frac{7-1}{2}=\frac{6}{2}=3$

Center of circle C: (3,3)

The radius of C is half the distance between A and B:

$d=\sqrt{(1-5)^2+(-1-7)^2}$

$d=\sqrt{16+64}=\sqrt{80}=\sqrt{16*5}=4\sqrt{5}$

The radius of C is d/2:

$r =4\sqrt{5}/2 = 2\sqrt{5}$

Center: (3,3)

Radius: $2\sqrt{5}$

8 0

3 years ago