Determine if (3,-4) is a solution to y < 2x – 5.

1 answer:

6 0

You would plug in the ordered pair into the equation.

1. Put the y value from the ordered pair in the y spot, and the x value in the x spot.

2. add up the x side

Does it equal the y side?

Im a bit confused as the question says “&lt” at least on my end? I’m not sure if that’s just the way it ended up being written or if it means something. Sorry if my answer doesn’t apply :(. But if it does, I hope it helps!

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At 6:00 p.m. the temperature was –5°F outside. By midnight the temperature had dropped 12 degrees. What was the temperature at m

USPshnik [31]

-5 - 12 = -17

Starts at -5 degrees, then it drops another 12, so you subtract 12 from -5.

6 0

3 years ago

Read 2 more answers

4- A manufacturing process produces items whose weights are normally distributed. It is known that 22.57% of all the items produ

galben [10]

Answer:

$\\ \mu = 118\;grams\;and\;\sigma=30\;grams$

Step-by-step explanation:

We need to use z-scores and a standard normal table to find the values that corresponds to the probabilities given, and then to solve a system of equations to find $\\ \mu\;and\;\sigma$ .

<h3>First Case: items from 100 grams to the mean</h3>

For finding probabilities that corresponds to z-scores, we are going to use here a <u>Standard Normal Table </u><u><em>for cumulative probabilities from the mean </em></u><em>(Standard normal table. Cumulative from the mean (0 to Z), 2020, in Wikipedia) </em>that is, the "probability that a statistic is between 0 (the mean) and Z".

A value of a z-score for the probability P(100<x<mean) = 22.57% = 0.2257 corresponds to a value of z-score = 0.6, that is, the value is 0.6 standard deviations from the mean. Since this value is <em>below the mean</em> ("the items produced weigh between 100 grams up to the mean"), then the z-score is negative.

Then

$\\ z = -0.6\;and\;z = \frac{x-\mu}{\sigma}$

$\\ -0.6 = \frac{100-\mu}{\sigma}$ (1)

<h3>Second Case: items from the mean up to 190 grams</h3>

We can apply the same procedure as before. A value of a z-score for the probability P(mean<x<190) = 49.18% = 0.4918 corresponds to a value of z-score = 2.4, which is positive since it is after the mean.

Then

$\\ z =2.4\;and\; z = \frac{x-\mu}{\sigma}$