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patriot [66]
2 years ago
15

What is 7 divided by 2/3

Mathematics
1 answer:
soldier1979 [14.2K]2 years ago
3 0

Answer:

10.5

Step-by-step explanation:

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22.5+7(n-34) simplified
Aneli [31]
22.5 + 7n - 238 \\ 7n - 215.5
7 0
3 years ago
Drag each tile to the correct box consider the given functions f,g and h place the tiles in order from least to greatest accordi
Alja [10]

Answer:

Step-by-step explanation:

By definition, the average rate of change of a function f over an interval [a,b] is given by

\dfrac{f(b)-f(a)}{b-a}

compute the quantity

\dfrac{f(3)-f(0)}{3}

for all the three function

Average rate of change of f:

We will simply use the table to check the values for f(3) and f(0):

\dfrac{f(3)-f(0)}{3}=\dfrac{10-1}{3} = 3

Average rate of change of g:

We will use the graph to to check the values for g(3) and g(0):

\dfrac{g(3)-g(0)}{3}=\dfrac{8-1}{3} = \dfrac{7}{3}

Average rate of change of h:

We can plug the values in the equation to get h(3) and h(0):

h(3)=3^2+3-6=9+3-6=6,\quad h(0)=0^2+0-6=-6

And so the average rate of change is

\dfrac{h(3)-h(0)}{3}=\dfrac{6-(-6)}{3} = 4

3 0
3 years ago
A circular swimming pool has a diameter of 40 meters. The depth of the pool is constant along west-east lines and increases line
Nataliya [291]

Answer:

Volume is 2000\pi\ m^{3}

Solution:

As per the question:

Diameter, d = 40 m

Radius, r = 20 m

Now,

From north to south, we consider this vertical distance as 'y' and height, h varies linearly as a function of y:

iff

h(y) = cy + d

Then

when y = 1 m

h(- 20) = 1 m

1 = c.(- 20) + d = - 20c + d              (1)

when y = 9 m

h(20) = 9 m

9 = c.20 + d = 20c + d                  (2)

Adding eqn (1) and (2)

d = 5 m

Using d = 5 in eqn (2), we get:

c = \frac{1}{5}

Therefore,

h(y) = \frac{1}{5}y + 5

Now, the Volume of the pool is given by:

V = \int h(y)dA

where

A = r\theta

A = rdr\ d\theta

Thus

V = \int (\frac{1}{5}y + 5)dA

V = \int_{0}^{2\pi}\int_{0}^{20} (\frac{1}{5}rsin\theta + 5) rdr\ d\theta

V = \int_{0}^{2\pi}\int_{0}^{20} (\frac{1}{5}r^{2}sin\theta + 5r}) dr\ d\theta

V = \int_{0}^{2\pi} (\frac{1}{15}20^{3}sin\theta + 1000) d\theta

V = [- 533.33cos\theta + 1000\theta]_{0}^{2\pi}

V = 0 + 2\pi \times 1000 = 2000\pi\ m^{3}

7 0
3 years ago
Write the expression as a single logarithm
Yakvenalex [24]

\log _a(6w+1)^{7} + \log _a(w+7)^{\frac{1}{5}} \\ \log _a(6w+1)^{7} + \log _a\sqrt[5]{(w+7)}\\\log _a((6w+1)^{7} (\sqrt[5]{(w+7)}))

4 0
2 years ago
In the given diagram , TY is a tangent to the circle TVS . If <SVT = 48° and |VS| = |ST| . What is < VTY.​
ycow [4]

Answer:

  • 84°

Step-by-step explanation:

∠VTY is the tangent chord angle

  • Tangent chord angle is the half of the intercepted arc

∠TSV is the inscribed angle.

  • Inscribed angle is the half of the intercepted arc

<u>Since both of the mentioned angles refer to same arc, they are of same value.</u>

  • ∠VTY = ∠TSV

ΔTVS is isosceles as VS = ST, therefore the opposite angles are same.

  • m∠T = m∠V = 48°

<u>The measure of angle S</u>

  • m∠S = 180° - 2*48° = 84°

<u>The required angle</u>

  • m∠VTY = 84°
4 0
3 years ago
Read 2 more answers
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