Step-by-step explanation:
part A:
ABCD is transformed to obtain figure A′B′C′D′:
1) by reflection over x-axis, obtain the image :
A(-4,-4) B(-2,-2) C(-2, 1) D(-4, -1)
2) by translation T (7 0), obtain the image :
A'(3,-4) B'(5,-2) C'(5, 1) D'(3, -1)
part B:
the two figures are congruent.
the figures that transformed by reflection either or translation will obtain the images with the same shape and size (congruent)
Answer:
A and X
Step-by-step explanation:
Got it right on edge-nuity
<span>0.48333333333 or if u round it off it would be 0.48</span>
The perimeter would be (24x - 40)/(x^2 - 4x).
In order to find this, first double the length and width as you would to find any perimeter.
7/(x - 4) * 2 = 14/(x - 4)
5/x * 2 = 10/x
Now to add those together, we need to give them common denominators. In order to do that with the first one, we need to multiply by x/x
14/(x - 14) * x/x = 14x/(x^2 - 14x)
Then we can do the same with the second part by multiplying by (x - 4)/(x - 4)
10/x * (x - 4)/(x - 4) = (10x - 40)/(x^2 - 14x)
Now we can add the two together
14x/(x^2 - 14x) + (10x - 40)/(x^2 - 14x) = (24x - 40)/(x^2 - 14x)
Answer:
the answer is d
<em>The square root property should have been applied to both complete sides of the equation instead of to select variables.
</em>
<em />
Step-by-step explanation: i just took the test on edge
