Answer:
The percent composition of CuO is 80%(Cu) and 20%(O)
Explanation:
Given:
Percent (%) Composition of CuO
Cu = 1 x 50g - Multiply by one as there is one Cu
O = 1 x 12.5g - Multiply by one as there is one O
CuO = 62.5g
% for Cu = 50g over 62.5 multiplied by 100 = 80%
% for O = 12.5g over 62.5 multiplied by 100 = 20%
Final Answer :
Percent (%) Composition of CuO = 80% (Cu) & 20% (O)
Answer:
pretty sure they're called groups
Answer: 0.25 mole PH3
Explanation: 1 mole of PH3 is equal to its molar mass P= 31 , H 1x3 = 34g
Solution:
8.5 g PH3 x 1 mole PH3 / 34 g PH3
= 0.25 mole PH3
Answer:
Two (2) types of ions
Explanation:
Metal ions (cations) and negatively charged ions (anions) of either chloride, carbonate, sulphides or hydroxides are present during the selective precipitation.
Majorly, the process determines the metal ions present by initiating precipitation as certain conditions.
I hope this was helpful.