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lesantik [10]
3 years ago
11

Which of the following polyatomic ions has a 3- ionic charge?

Chemistry
1 answer:
ch4aika [34]3 years ago
4 0

Answer: Option (a) is the correct answer.

Explanation:

Poly means many and polyatomic ions means an ion(s) with two or more different atoms.

Out of the given options, phosphate ion is the polyatomic ion which has an ionic charge of 3-.

The formula depicting a phosphate ion is PO_{4}^{3-}.

Whereas Nitrate, Sulfate, Hydroxide , Bicarbonate does not carry or have a 3- ionic charge.

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Write a hypothesis:<br> What is the mole ratio of the cation and the anion in a precipitate?
tankabanditka [31]

Answer:

The mole ratio of the cation and the anion in a precipitate is a simple fraction. ( im sorry if this dosent help a lot.)

Explanation:

8 0
2 years ago
How would this change affect the food web?check all that apply
klio [65]

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7 0
3 years ago
Which polyatomic ion is found in the compound represented by the formula NaHCO3? (1) acetate (3) hydrogen sulfate (2) hydrogen c
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5 0
3 years ago
Salt is poured from a container at 10 cm³ s-¹ and it formed a conical pile whose height at any time is 1/5 the radius of the abo
Romashka-Z-Leto [24]

Answer:

\displaystyle \frac{dh}{dt} = \frac{1}{10 \pi}

Explanation:

Volume of a cone:

  • \displaystyle V=\frac{1}{3} \pi r^2 h

We have \displaystyle \frac{dV}{dt} = \frac{10 \ cm^3}{sec} and we want to find \displaystyle \frac{dh}{dt} \Biggr | _{h\ =\ 6}= \ ? when the height is 2 cm.

We can see in our equation for the volume of a cone that we have three variables: V, r, and h.

Since we only have dV/dt and dh/dt, we can rewrite the equation in terms of h only.

We are given that the height of the cone is 1/5 the radius at any given time, 1/5r, so we can write this as r = 5h.

Plug this value for r into the volume formula:

  • \displaystyle V =\frac{1}{3} \pi (5h)^2 h  
  • \displaystyle V =\frac{1}{3} \pi \ 25h^3

Differentiate this equation with respect to time t.

  • \displaystyle \frac{dV}{dt}  =\frac{25}{3} \pi \ 3h^2 \ \frac{dh}{dt}
  • \displaystyle \frac{dV}{dt}  =25 \pi h^2 \ \frac{dh}{dt}

Plug known values into the equation and solve for dh/dt.

  • \displaystyle 10 = 25 \pi (2)^2  \ \frac{dh}{dt}
  • \displaystyle 10 = 100 \pi  \ \frac{dh}{dt}  

Divide both sides by 100π to solve for dh/dt.

  • \displaystyle \frac{10}{100 \pi} = \frac{dh}{dt}
  • \displaystyle \frac{dh}{dt} = \frac{1}{10 \pi}

The height of the cone is increasing at a rate of 1/10π cm per second.

7 0
3 years ago
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