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2 years ago

5

PLZ HELP ASAP MARK BRAINLIEST VIEW PICTURE!!

1 answer:

krok68 [10]2 years ago

7 0

Answer: The second option

Step-by-step explanation: 14mph times 5 equal 70. 5 hours after 6 am is 11 am. 70 divided by 20 is 3.5. 3.5 hours after 6 am is 9:30. Hence 9:30 to 11

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11. The regression equation y=2x + 8 represents how many minutes a sound will last after applying x pounds of pressure to the sy

Sidana [21]

Then y=2(4)+8
=8+8
=16

8 0

3 years ago

The radius of a basketball is 4.7 inches.what the volume of the basketball? Round to the nearest 10

asambeis [7]

The formula for the volume of a sphere is $V= \frac{4}{3} \pi r^3$ . Plugging in 4.7 for your radius, we get $V= \frac{4}{3} \pi 4.7^2= \frac{4}{3} \pi 22.09= \frac{88.36}{3} \pi$ , which is roughly 29.453π≈92.530.

4 0

3 years ago

Read 2 more answers

Plz help I have been struggling on this one

tamaranim1 [39]

the first answer is 93000000 and the second answer is 240000

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3 years ago

You know the measure of the exterior angle which forms a linear pair with the vertex angle. Describe two ways you can find measu

aev [14]

Answer:

Step-by-step explanation:

A linear pair are two given angles whose sum is equal to $180^{o}$ .

Let the exterior angle be represented by $x^{o}$ , and the three interior angles of the triangle be represented by $a^{o}$ , $b^{o}$ and $c^{o}$ .

Assume that the vertex angle $c^{o}$ is the linear pair to the exterior angle $x^{o}$ .

i.e $x^{o}$ + $c^{o}$ = $180^{o}$ (sum of angles on a straight line)

Thus,

i. $a^{o}$ + $b^{o}$ = $x^{o}$ (sum of two opposite interior angles is equal to an exterior angle)

⇒ $a^{o}$ = $x^{o}$ - $b^{o}$

Also,

$b^{o}$ = $x^{o}$ - $a^{o}$

But,

$a^{o}$ + $b^{o}$ + $c^{o}$ = $180^{o}$ (sum of angles in a triangle)

⇒ $c^{o}$ = $180^{o}$ - ( $a^{o}$ + $b^{o}$ )

and

$a^{o}$ + $b^{o}$ = $180^{o}$ - $c^{o}$

ii. $a^{o}$ + $b^{o}$ + $c^{o}$ = $180^{o}$ (sum of angles in a triangle)

$a^{o}$ = $180^{o}$ - ( $b^{o}$ + $c^{o}$ )

Also,

$a^{o}$ + $b^{o}$ = $x^{o}$

⇒ $b^{o}$ = $x^{o}$ - $a^{o}$

$c^{o}$ = $180^{o}$ - $x^{o}$

8 0

3 years ago

Help help help help pls

Monica [59]

Answer:

$\theta = 82.2^\circ$

Step-by-step explanation:

$Let \ \angle BAC = \theta$

Opposite = BC ,

Adjacent = AB = x = 3 ,

Hypotenuse = AC = y = 22

<em><u>Using trigonometric ratios.</u></em>

$sin \theta = \frac{opposite}{hypotenuse }\\\\cos \theta = \frac{adjacent}{hypotenuse}\\\\tan \theta = \frac{opposite}{adjacent}$

Since we have adjacent and hypotenuse we use cosine's ratio

to find the angle.

$cos \theta = \frac{x}{y} = \frac{3}{22} \\\\\theta = cos^{-1} \frac{3}{22} = 82.16 = 82.2^\circ$

6 0

3 years ago