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4 years ago

For f (c)=2x+1 and g(x)=x^2 - 7 find (f-g)(x)

Mathematics

1 answer:

Veronika [31]4 years ago

7 0

Answer:

$\large\boxed{D.\ -x^2+2x+8}$

Step-by-step explanation:

$(f-g)(x)=f(x)-g(x)\\\\f(x)=2x+1,\ g(x)=x^2-7\\\\\text{substitute:}\\\\(f-g)(x)=(2x+1)-(x^2-7)=2x+1-x^2-(-7)=2x+1-x^2+7\\\\=-x^2+2x+(1+7)=-x^2+2x+8$

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Step-by-step explanation:

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3 years ago

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Leno4ka [110]

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4 years ago

Please help x = -2 and y = -5

Darina [25.2K]

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Step-by-step explanation:

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3 years ago

What is the answer? x^2 + 4x - 6 = 0

vodka [1.7K]

First we have to find $\Delta$ from the equation $b^{2} -4ac$ where a, b and c are consecutive coefficients of the equation. In this case: $a=1, b=4, c=-6$

 $\Delta =4^2-4*(-6)=16+24=40$ , 

Later we will need to use $\sqrt{\Delta}$ sofor us $\sqrt{40}$ . It can be then simplified to $2 \sqrt{10}$ .

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The answer for your question:
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4 years ago