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3 years ago

Please Help me

Mathematics

2 answers:

RideAnS [48]3 years ago

8 0

D.27 hope this helped

inessss [21]3 years ago

7 0

The answer is 27 because the are nine options which can be recombined in 3 independent ways. Therefore, 9*3=27

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A phone is regularly priced at $350. If you get it on sale for 15% off, how much do you pay?

Nesterboy [21]

52.5

Explanation:
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2 years ago

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Carter and his family are driving from Atlanta to Raleigh. They drive for 2 hours and 45 minutes at an average speed of 60 miles

Blizzard [7]

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3 years ago

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What is the slope of the line with points A and B?

marshall27 [118]

Answer:

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2 years ago

Use the diagram to complete the statement. Triangle J K L is shown. Angle K J L is a right angle. Angle J K L is 52 degrees and

zzz [600]

Answer:

$\bold{sin(38^\circ)=cos(52^\circ)}$

Step-by-step explanation:

Given that $\triangle KJL$ is a right angled triangle.

$\angle JKL = 52^\circ\\\angle KLJ = 38^\circ$

and

$\angle KJL = 90^\circ$

Kindly refer to the attached image of $\triangle KJL$ in which all the given angles are shown.

To find:

sin(38°) = ?

a) cos(38°)

b) cos(52°)

c) tan(38°)

d) tan(52°)

Solution:

Let us use the trigonometric identities in the given $\triangle KJL$ .

We have to find the value of sin(38°).

We know that sine trigonometric identity is given as:

$sin\theta =\dfrac{Perpendicular}{Hypotenuse}$

$sin(\angle JLK) = \dfrac{JK}{KL}\\OR\\sin(38^\circ) = \dfrac{JK}{KL}$ ....... (1)

Now, let us find out the values of trigonometric functions given in options one by one:

$cos\theta =\dfrac{Base}{Hypotenuse}$

$cos(\angle JLK) = \dfrac{JL}{KL}\\OR\\cos(38^\circ) = \dfrac{JL}{KL}$ ....... (2)

By (1) and (2):

sin(38°) $\neq$ cos(38°).

$cos(\angle JKL) = \dfrac{JK}{KL}\\OR\\cos(52^\circ) = \dfrac{JK}{KL}$ ...... (3)

Comparing equations (1) and (3):

we get the both are same.

$\therefore \bold{sin(38^\circ)=cos(52^\circ)}$

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3 years ago

Two teachers are taking 8 students to the aquarium. Adult admission is $12, but students receive a discount of $3 off

zhuklara [117]

Answer:

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3 years ago