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Diano4ka-milaya [45]
3 years ago
8

Can you help me with this problem

Mathematics
1 answer:
snow_lady [41]3 years ago
4 0
Since there are no actual values, I guess we just have to isolate the b.

2A=bh (multiply both sides by 2)
2A/h=b (divide by h)

hope this helps
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What is -3 2/3 x (-2 1/4)? A. -8 1/4. B. -6 1/6 C. 6 1/6. D. 8 1/4
juin [17]

Answer:

8 1/4

Step-by-step explanation:

Solution by Formulas

converting mixed numbers to fractions, our initial equation becomes,

−11 -9

3×4

Applying the fractions formula for multiplication,

−11×−9

3×4

=99

12

Simplifying 99/12, the answer is

=814

7 0
3 years ago
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Solve for X. round to the nearest tenth. 2 5 x 3.5
notka56 [123]
I would say 2.....sorry if I am wrong
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3 years ago
A certain town never has two sunny days in a row. Each day is classified as being either sunny, cloudy (but dry), or rainy. If i
11111nata11111 [884]

Answer:

the proportion of days that are Sunny is 0.2

Step-by-step explanation:

Given the data in the question;

Using markov chain;

3 states; Sunny(1), Cloudy(2) and Rainy(3)

Now, based on given conditions, the transition matrix can be obtained in the following way;

\left[\begin{array}{ccc}0&0.5&0.5\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]

so let the proportion of sunny, cloudy and rainy days be S, C and R respectively.

such that, from column 1

S = 0.25C + 0.25R   -------------let this be equation 1

from column 2

0.5C = 0.5S + 0.25R

divided through by 0.5

C = S + 0.5R ---------------------- let this be equation 2

now putting equation 2 into equation;

S = 0.25(S + 0.5R) + 0.25R

S = 0.25S + 0.125R + 0.25R

S - 0.25S = 0.375R

0.75S = 0.375R

S = 0.375R / 0.75

S = 0.5R

Therefore,

from equation 2; C = S + 0.5R

input S = 0.5R

C = 0.5R + 0.5R

C = R

Now, we know that, the sum of the three proportion should be equal to one;

so

S + C + R = 1

since C = R and S = 0.5R

we substitute

0.5R + R + R = 1

2.5R = 1

R = 1/2.5

R = 0.4

Hence, the proportion of days that are Rainy is 0.4

C = R

C = 0.4

Hence, the proportion of days that are Cloudy is 0.4

S = 0.5R

S = 0.5(0.4)

S = 0.2

Hence, the proportion of days that are Sunny is 0.2

8 0
3 years ago
What is 0.875 as a fraction following decimal expansion
Lady bird [3.3K]

Answer: 7/8

Step-by-step explanation:

7 0
3 years ago
If AA and BB are two disjoint events with P(A)=0.15P(A)=0.15 and P(B)=0.75P(B)=0.75, find the following probabilities:
zubka84 [21]

Answer:

a 0

b) 0.9

c) 0.85

d) 0.25

e) 0.1

f) 0.0375

Step-by-step explanation:

a)

As A and B are two disjoints events, then P(A and B) is

P(A and B)=0

b)

As A and B are two disjoints events, then P(A or B) is

P(A or B)=P(A)+P(B)

P(A or B)=0.15+0.75=0.9

c)

P(not A)=1-P(A)

P(not A)=1-0.15=0.85

d)

P(not B)=1-P(B)

P(not B)=1-0.75=0.25

e)

P(not (A or B))=1-P(A or B)

P(not (A or B))=1-0.9=0.1

f)

P(A and (not B))=P(A)*P(not B)

P(A and (not B))=0.15*0.25=0.0375

5 0
3 years ago
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