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1 year ago

Read and answer the following:

Mathematics

2 answers:

netineya [11]1 year ago

6 0

The answer of you're question is C

Digiron [165]1 year ago

3 0

Answer:

here ,

origin means (0,0)

so ,

h and k are 0 and 0

and diameter ( d) is 4

r = d/2

using formula

(x-h)^2 +( y-k)^2 = r^2

(x-0)^2 +( y-0)^2= 2^2

x^2+y^2= 4 is the equation.

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Find the measure of an angle and its complement if one angle measures 24 degrees more than the other.

Vera_Pavlovna [14]

Complementary angles = 90

x+y =90

y=x+24

substitute this in to the equation

x+x+24=90

2x+24=90

subtract 24 from each side

2x = 66

divide by 2

x=33

y = 33+24

y=57

Answer: 33, 57

6 0

3 years ago

Anybody know the answer?

expeople1 [14]

Y=x-2+3
I put x-2 because when graphing it's the opposite so it would technically be x+2
Then the +3 for the y chords which go up by 3 ! if this is wrong then try Y= (x-2)+3

8 0

2 years ago

Gabriel must practice piano at least 15 hours a week. This week he has practiced 6 hours so far. Piano lessons are part of Gabri

suter [353]

Answer:

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

The profit on a jacket can be found by the formula P=24x-125, where x is the number of jackets sold. What is the profit if 15 ja

horrorfan [7]

Your answer would be 235

5 0

2 years ago

Rafeeq bought a field in the form of a quadrilateral (ABCD)whose sides taken in order are respectively equal to 192m, 576m,228m,

Valentin [98]

Answer:

a. 85974 m²

b. 17,194,800 AED

c. 18,450 AED

Step-by-step explanation:

The sides of the quadrilateral are given as follows;

AB = 192 m

BC = 576 m

CD = 228 m

DA = 480 m

Length of a diagonal AC = 672 m

a. We note that the area of the quadrilateral consists of the area of the two triangles (ΔABC and ΔACD) formed on opposite sides of the diagonal

The semi-perimeter, s₁, of ΔABC is found as follows;

s₁ = (AB + BC + AC)/2 = (192 + 576 + 672)/2 = 1440/2 = 720

The area, A₁, of ΔABC is given as follows;

$Area\, of \, \Delta ABC = \sqrt{s_1\cdot (s_1 - AB)\cdot (s_1-BC)\cdot (s_1 - AC)}$

$Area\, of \, \Delta ABC = \sqrt{720 \times (720 - 192)\times (720-576)\times (720 - 672)}$

$Area\, of \, \Delta ABC = \sqrt{720 \times 528 \times 144 \times 48}$ = 6912·√(55) m²

Similarly, area, A₂, of ΔACD is given as follows;

$Area\, of \, \Delta ACD= \sqrt{s_2\cdot (s_2 - AC)\cdot (s_2-CD)\cdot (s_2 - DA)}$

The semi-perimeter, s₂, of ΔABC is found as follows;

s₂ = (AC + CD + D)/2 = (672 + 228 + 480)/2 = 690 m

We therefore have;

$Area\, of \, \Delta ACD = \sqrt{690 \times (690 - 672)\times (690 -228)\times (690 - 480)}$

$Area\, of \, \Delta ACD = \sqrt{690 \times 18\times 462\times 210} = \sqrt{1204988400} = 1260\cdot \sqrt{759} \ m^2$

Therefore, the area of the quadrilateral ABCD = A₁ + A₂ = 6912×√(55) + 1260·√(759) = 85973.71 m² ≈ 85974 m² to the nearest meter square

b. Whereby the cost of 1 meter square land = 200 AED, we have;

Total cost of the land = 200 × 85974 = 17,194,800 AED

c. Whereby the cost of fencing 1 m = 12.50 AED, we have;

Total perimeter of the land = 576 + 192 + 480 + 228 = 1,476 m

The total cost of the fencing the land = 12.5 × 1476 = 18,450 AED

4 0

2 years ago