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3 years ago

Use angle relationships to travel through the parallel maze following the prompts below.

Mathematics

1 answer:

Dmitriy789 [7]3 years ago

5 0

Answer:

because they are connected

Step-by-step explanation:

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Find the value of x.<br> 12<br> 12<br> x = [?]

daser333 [38]

Step-by-step explanation:

step 1. The segment x is made up of 2 equal lines which are connected in the middle to another segment 12 units long.

step 2. the intersection of these two segments must create a 90° angle because the two lines are equal.

step 3. The lower segments are identical to the upper segments.

step 4. therefore x = 11(2) = 22.

8 0

3 years ago

Roseanne is making chocolate chip cookies for dessert the recipe for one batch of chocolate chip cookies calls for 2 1/2 cups of

umka21 [38]

Answer:

8 3/4 cups of sugar

Step-by-step explanation:

1 batch of chocolate chip cookies ↔ 2 1/2 cups of sugar

3 1/2 batch of chocolate chip cookies ↔ 3 1/2 * 2 1/2 cups of sugar

3 1/2 * 2 1/2 = 7/2 * 5/2 = 35/4 = 8 3/4 = 8.75

4 0

3 years ago

Heavy football players: Following are the weights, in pounds, for offensive and defensive linemen on a professional football tea

Vaselesa [24]

Answer:

a) Mean = 302.25, Median = 309.5

b) Mean = 276.08, Median = 272

c) Offensive linemen tends to be heavier.

Step-by-step explanation:

We are given the following in the question:

Offense: 325, 292, 316, 308, 325, 263, 302, 311, 265, 329, 267, 324

Defense: 265, 276, 255, 306, 317, 281, 268, 282, 260, 261, 256, 286

a) mean and median weight for the offensive linemen

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{3627}{12} = 302.25$

$Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}$

Sorted Data: 263, 265, 267, 292, 302, 308, 311, 316, 324, 325, 325, 329

$\text{Median} = \dfrac{6^{th}+7^{th}}{2}=\dfrac{308+311}{2} = 309.5$

b) mean and median weight for the defensive linemen

$Mean =\displaystyle\frac{3313}{12} = 276.08$

Sorted Data: 255, 256, 260, 261, 265, 268, 276, 281, 282, 286, 306, 317

$\text{Median} = \dfrac{6^{th}+7^{th}}{2}=\dfrac{268+276}{2} = 272$

c) Comparison

On comparing the mean and median of offensive and defensive linemen, offensive tends to be heavier

4 0

3 years ago

Solve for y: -5(2y+3) +5=40

Yanka [14]

Answer:

Step-by-step explanation:

-5(2y + 3) +5 = 40

-10y - 15 + 5 = 40

-10y = 40 +15 - 5

-10y = 50

y = $\frac{50}{-10\\}$

y = -5

7 0

3 years ago

a survey is taken to determine which type of vehicle is shown most popular. the data is shown in the bar graph below. what can y

matrenka [14]

I believe it could be G or I(j?)

7 0

4 years ago