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dimulka [17.4K]
3 years ago
5

Help please I’m really having trouble on my class work please help w all 3

Mathematics
1 answer:
tatuchka [14]3 years ago
5 0

Answer:

Number 4. A

Number 5. B

Number 6. B

Step-by-step explanation: On god

Can You write me a three-paragraph reflection about how the first trimester went. Since I helped you plz

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Which of the following is the graph of y = ex + 1?
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Katie is 6/10 of the way to Brianna's house. Larry is 7/10 of the way to Brianna's house. How much closer to Brianna''s house is
SVETLANKA909090 [29]
I think Larry is 1/10 closer to Brianna's than Katie.
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3 years ago
V-5.65=6.93<br> solve for v
Alex

Step-by-step explanation:

v-5.65=6.93

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hope it helps.

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Please find the fully simplified intercept form!!!! Will mark Brianliest !!!!!!!!!!!
photoshop1234 [79]

Answer:

  • y = -1/3x  - 8

Step-by-step explanation:

<u>Slope intercept form:</u>

  • y = mx + b

<u>Use two points from the graph:</u>

  • (0, -8) and (3, -9)

<u>The first point is the y-intercept: </u>

  • b = -8

<u>Find the slope using the slope formula:</u>

  • m = (y2 - y1)/(x2 - x1)
  • m = (-9 - (-8))/3 = -1/3

<u>The equation is:</u>

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7 0
3 years ago
How to solve this problem step by step. Make brainliest answer if its done. Please
sladkih [1.3K]

D is halfway between A and B

so the coordinates of D are (2,2)

E is halfway between A and C so the coordinates of E are (-1,1)

now you need to find the gradient/slope of DE and BC using the formula:

\frac{y2 - y1}{x2 - x1}

<h3><u>G</u><u>r</u><u>a</u><u>d</u><u>i</u><u>e</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>D</u><u>E</u><u>:</u><u> </u></h3>

SUB IN COORDINATES OF D AND E

\frac{1 - 2}{ - 1 - 2}

therefore the gradient of DE is 1/3.

<h3><u>G</u><u>r</u><u>a</u><u>d</u><u>i</u><u>e</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>B</u><u>C</u><u>:</u></h3>

<em>S</em><em>U</em><em>B</em><em> </em><em>I</em><em>N</em><em> </em><em>C</em><em>O</em><em>O</em><em>R</em><em>D</em><em>I</em><em>N</em><em>A</em><em>T</em><em>E</em><em>S</em><em> </em><em>O</em><em>F</em><em> </em><em>B</em><em> </em><em>A</em><em>N</em><em>D</em><em> </em><em>C</em>

<em>\frac{ - 2 - 0}{ - 3 - 3}</em>

therefore the gradient of BC is -2/-6 which simplifies to 1/3.

<h3>therefore, BC and DE are parallel as they both have a gradient/slope of 1/3 and parallel lines have the same gradient</h3>

6 0
4 years ago
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