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dimulka [17.4K]
3 years ago
5

Help please I’m really having trouble on my class work please help w all 3

Mathematics
1 answer:
tatuchka [14]3 years ago
5 0

Answer:

Number 4. A

Number 5. B

Number 6. B

Step-by-step explanation: On god

Can You write me a three-paragraph reflection about how the first trimester went. Since I helped you plz

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forgot how to do it
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Answer:

It's F. none of the points

Step-by-step explanation:

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there's 135 feet of masking tape on a roll Henry has 6 rolls how many feet of masking tape does he have in all
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135 x 6 = 810

So Henry has 810 feet of masking tape.
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4 years ago
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Your company is considering offering 900 employees the opportunity to transfer to its new headquarters in Ottawa and, as personn
Tresset [83]

Answer:

a) P(100M) = \frac{100C100*1100C800}{1200C900}

b) P(1M) = \frac{100C1*1199C899}{1200C900}

Step-by-step explanation:

Extract information from question:

Manager = M = 100

Factory Workers = FW = 200

Miscellaneous Staff = MS = 900

Total Workers = 1200

Moving Workers = 900

'Combinations' are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations the formula below is used:

nCr=\frac{n!}{r!(n-r)!}

where 'n' is the total number of items

'r' is the number of items being chosen at a time

The '!' is the factorial function which is the product of all integers equal to and less than the given integer.

Combinations can be calculated manually using the formula above or by using the nCr function on a scientific calculator.

Part a)

Combinations of all 100 managers being selected

C = nCr=\frac{n!}{r!(n-r)!}

C(100M) = 100C100

Combinations of 800 of factory workers and miscellaneous staff being selected out of 1100 remaining staff

C = nCr=\frac{n!}{r!(n-r)!}

C(800FW/MS) = 1100C800

Total possible unspecified combinations of 900 staff being selected out of 1200 total staff

C = nCr=\frac{n!}{r!(n-r)!}

C(900M/FW/MS) = 1200C900

Probability of all 100 managers being selected:

P(100M) = \frac{100C100*1100C800}{1200C900}

Part b)

Combinations of 1 out of 100 managers being selected

C = nCr=\frac{n!}{r!(n-r)!}

C(1M) = 100C1

Combinations of 899 of managers, factory workers and miscellaneous staff being selected out of 1199 remaining staff

C = nCr=\frac{n!}{r!(n-r)!}

C(899M/FW/MS) = 1199C899

Total possible unspecified combinations of 900 staff being selected out of 1200 total staff

C = nCr=\frac{n!}{r!(n-r)!}

C(900M/FW/MS) = 1200C900

Probability of being the 1 manager being selected:

P(1M) = \frac{100C1*1199C899}{1200C900}

3 0
3 years ago
Ten times the square of a non zero number is equal to forty times the number, what is the number?
Liono4ka [1.6K]

Answer:

  4

Step-by-step explanation:

Let x represent the number. The problem statement tells us ...

  10x² = 40x

  x = 4 . . . . . . . divide by 10x

The number is 4.

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Andrew borrowed $700 from the bank to start a pressure washing business. The bank charged a simple interest rate of 7% per year.
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Answer:6%

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