Answer:
The number of hours that she work for the fast food is 11
The number of hours that she mowed is 5
Step-by-step explanation:
let x= hours spent mowing
y= hours spent at the food joint.
we can now form an equations from the figures given.
x+y=16...*
10.5x+4.25y=136.75...**
solving the two equations simultaneously using the substitution method or the eliminating method,
x=11 hours
y=5 hours
Answer: 20%
Step-by-step explanation:
The 150 students in the marching band and 30 of the students play the trumpet. To get the percentage of students that play the trumpet, we divide 30 by 150 and then multiply by 100. This can be written as:
= 30/150 × 100
= 0.2 × 100
= 20%
The percentage of students that play the trumpet is 20%
Answer:
Yes.
Step-by-step explanation:
Forget about the negative sign for now.
Just compare 5/7 and 4/5 first.
Find the common denominator so it's easy to determine which one is bigger/larger.
5/7=25/35 and 4/5=28/35
From here, you can tell which one is bigger/larger, right?
Definitely, 25/35<28/35.
5/7<4/5, but don't forget the negative sign.
It's -5/7 compared to -4/5, so the answer is yes, -5/7>-4/5.
Answer:
Exact answer not possible: See below.
Step-by-step explanation:
The total that Tammy would pay is the sum of 2A and 5B, where A and B are the number of candies costing $2 and $5, respectively. Therefore:
2A + 2B = Total Spent
We are told Tammy spent <u>at least</u> $75, which can be written as "Total Spent > $75."
The equation becomes 2A + 5B > 75
Rearranging:
2A + 5B > 75
2A > 75 - 5B
A > (75 - 5B)/2
To find the maximum of the candy A bought, one can try different values of A and B that result in a total of at least $75. If the amount spent were $75 exactly, a solution would be 35 A (for $70), leaving $5 for 1 candy B. But we don't know the exact amount. The problems states "at least $75." As far as we know, Tammy may have spent $105, $405, $1,005, or even $4,005 (200 A and 1 B). One cannot pick a maximum simply since the maximum spent is not defined. The next possible value above $75 would be $77, which represents 36 A and 1 B candies.
