Answer:
The value at the end of year 2 is $4400.
Step-by-step explanation:
The best approach here is to determine the expression for the line depreciation and then calculate the depreciation value at x = 2 years.
A line is given by

where m is the slope and b the bias (aka y-intercept). You can determine both directly from what is given. The slope is change in y divided by change in x. We know that over 5 years the car loses (500-7000)=-6500 in value. So, the slope is m=-6500/5 (note the negative sign). At time 0, the y-intercept is 7000, since that is the initial value (at year 0). So our line function is fully identified:

and gives you the value of the car in any given year. To answer the question, we now plug in 2 as value of x:

First, convert all of the cm measurements to m measurements (so they are all the same unit measurement)
2000 cm = 20 m 800 cm = 8m
<u>Total Perimeter </u>(Note that circumference of a semi-circle is 2 π r/2 = π r)
Add up the lengths of all of the outside edges. I am going to start on the top and move counter-clockwise:
40 + π (10) + 8 + 25 + 8 + (40 - 25 - 10) + 8 + 10 + 8 + π(10)
= 40 + 10π + 41 + (5) + 26 + 10π
= 112 + 20π
= 112 + 62.8
= 174.8
Answer: 174.8 m
<u>Total Area</u>
Split the picture into 5 sections (2 semi-circles, top rectangle, bottom left rectangle, and bottom right rectangle). Find the area for each of those sections and then add their areas together to find the total area.
2 semi-circles is 1 Circle: A = π · r² ⇒ A = π(20/2)² = π(10)² = 100π ≈ 314
top rectangle: A = L x w ⇒ A = 40 x 20 = 800
bottom left rectangle: A = L x w ⇒ A = 25 x 8 = 200
bottom right rectangle: A = L x w ⇒ A = 10 x 8 = 80
Total = 314 + 800 + 200 + 80 = 1394
Answer: 1394 m²
You need to be more specific and show me the problem.
Hi, This is my answer. Check it out!!!!
(6.0 x 10^5) x (3.0 x 10^4) = (6 x 3) x 10^(5 + 4) = 18 x 10^9 = 1.8 x 10^10