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2 years ago

Jack's weight is 25 pounds more than twice Sally's weight. Find Jack's weight if together they weigh 225 pounds.

Mathematics

2 answers:

kramer2 years ago

4 0

Answer:

158 1/3

Step-by-step explanation:

Create an equation. J = JACK and S = SALLY

2s+25 = Jack

Jack + Sally = 225

2s+25+s = 225

3s+25 = 225

3s = 200

s = 66 2/3

66 2/3*2 = 133 1/3

133 1/3 + 25 = 158 1/3

sammy [17]2 years ago

3 0

Jack's weight if together they weigh 225 pounds will be 158(¹/₃).

<h3>
What is an expression?</h3>

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Given that Jack's weight is 25 pounds more than twice Sally's weight and the total weight is 225 pounds.

Create an equation. J = JACK and S = SALLY

2s+25 = Jack

Jack + Sally = 225

2s+25+s = 225

3s+25 = 225

3s = 200

s = 66(²/₃)

66(²/₃) x 2 = 133( ¹/₃)

133( ¹/₃) + 25 = 158( ¹/₃)

Therefore, Jack's weight if together they weigh 225 pounds will be 158(¹/₃).

To know more about an expression follow

brainly.com/question/1627455

#SPJ2

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luda_lava [24]

Let $f(x) = x^3 - 2x - 2$ . Then differentiating, we get

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We approximate $f(x)$ at $x_1=2$ with the tangent line,

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The $x$ -intercept for this approximation will be our next approximation for the root,

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Repeat this process. Approximate $f(x)$ at $x_2 = \frac95$ .

$f(x) \approx f(x_2) + f'(x_2) (x-x_2) = \dfrac{193}{25}x - \dfrac{1708}{125}$

Then

$\dfrac{193}{25}x - \dfrac{1708}{125} = 0 \implies x_3 = \dfrac{1708}{965}$

Once more. Approximate $f(x)$ at $x_3$ .

$f(x) \approx f(x_3) + f'(x_3) (x - x_3) = \dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125}$

Then

$\dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125} = 0 \\\\ \implies x_4 = \dfrac{5,881,319,037}{3,324,107,515} \approx 1.769292663 \approx \boxed{1.769293}$