When you multiply a negative times a negative, the product is

Mathematics

2 answers:

netineya [11]3 years ago

5 0

Positive
Ex- -5 x -7 = 35

evablogger [386]3 years ago

3 0

Positive use this technique the 2 negatives put them together and it makes a + which is a positive and when it’s a negative and positive it’ll be a negative because it’s alone

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The table shows the relationship between the number of Calories Lucie burns while jumping rope and the number of minutes she jum

iragen [17]

Answer:

The amount of calories Lucie will burn by jumping for 1 minute is 8 calories

Step-by-step explanation:

The given data values are;

Minutes ${}$ Calories Burned

40 ${}$ 320

80 ${}$ 640

120 ${}$ 960

160 ${}$ 1280

The value of calories burnt and the number of minutes of jump robe are seen to be directly proportional, such that we have;

40 minutes of jump rope will yield 320 calories burnt

Therefore we have;

1 minute of jump rope will yield 320/40 = 8 calories burnt

The amount of calories Lucie will burn by jumping for 1 minute = 8 calories.

8 0

3 years ago

Distance between parallel lines y=3x+10 and y=3x-20

Alecsey [184]

1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).

2. Use formula $d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}}$ to find the distance from point $(x_0,y_0)$ to the line Ax+By+C=0.

The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:

$d=\dfrac{|3\cdot 0-10-20|}{\sqrt{3^2+(-1)^2}}=\dfrac{30}{\sqrt{10}}=3\sqrt{10}$ .

3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.

Answer: $d=3\sqrt{10}$ .