<span>The correct answers are ‘distributive property' and ‘addition property of equality'. The distributive property can be observed between the first and second lines when the brackets are expanded. The addition property can be seen when -2x is added to both sides to change 6x + 10 - 2x = 22 + 2x - 2x into 4x + 10 = 22.</span>
Answer:
g ≤ 56
Step-by-step explanation:
56 + 14 ≤ 70
70 ≤ 70
Answer: D. (2*7)+(2*7)
4*7= 28
(2*7)+(2*7)
= 28
Answer:
a force of 1250lb is exerted
Step-by-step explanation:
since the force of the wind varies jointly as the area of the surface and the square of the velocity,
let f = force
a = area
velocity =v
from the above statement, we find out that
----1
that is
-----2
where k is a coefficent of proportionality
since velocity of wind in mph,v =50
and force in lb = 20
and surface area =![1/5 th ft^2](https://tex.z-dn.net/?f=1%2F5%20th%20ft%5E2)
from eqn 2
we have that
![20 =k*\frac{1}{5}* 50^2](https://tex.z-dn.net/?f=20%20%3Dk%2A%5Cfrac%7B1%7D%7B5%7D%2A%2050%5E2)
making k subject of the formula
we have that
![k =\frac{20}{\frac{1}{5} *50^2 } =\frac{1}{25} (lb.mph^-1.ft^-2)](https://tex.z-dn.net/?f=k%20%3D%5Cfrac%7B20%7D%7B%5Cfrac%7B1%7D%7B5%7D%20%2A50%5E2%20%7D%20%3D%5Cfrac%7B1%7D%7B25%7D%20%28lb.mph%5E-1.ft%5E-2%29)
that means that
---3
however, when velocity = 125mph
surface area =![2ft^2](https://tex.z-dn.net/?f=2ft%5E2)
putting values in eqn 3 we have
hence a force of 1250lb is exerted