Ask question

Ask question

All categories

jarptica [38.1K]

3 years ago

5

BIG POINTS ANSWER WITH DETAIL! Solve for x: 3x + 1 = 3x

1 answer:

Leni [432]3 years ago

6 0

There are no solutions to this problem,

Let's solve your equation step-by-step.
3
x
+
1
=
3
x
Step 1: Subtract 3x from both sides.
3
x
+
1
−
3
x
=
3
x
−
3
x
1
=
0
Step 2: Subtract 1 from both sides.
1
−
1
=
0
−
1
0
=
−
1

There are no solutions

You might be interested in

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an

igomit [66]

Answer:

$\frac{d}{dx}[f(x)+g(x)+h(x)] = \frac{9\cdot x^{8}}{\sqrt{1-x^{18}}} - 81\cdot x^{80}-2\cdot x$

Step-by-step explanation:

This derivative consist in the sum of three functions: $f(x) = 81\cdot \sin^{-1} x^{9}$ , $g(x) = - x^{81}$ and $h(x) = - x^{2}$ . According to differentiation rules, the derivative of a sum of functions is the same as the sum of the derivatives of each function. That is:

$\frac{d}{dx} [f(x)+g(x) + h(x)] = \frac{d}{dx} [f(x)]+\frac{d}{dx} [g(x)] +\frac{d}{dx} [h(x)]$

Now, each derivative is found by applying the derivative rules when appropriate:

$f(x) = 81\cdot \sin^{-1} x^{9}$ Given

$f'(x) = \frac{9\cdot x^{8}}{\sqrt{1-x^{18}}}$ (Derivative of a arcsine function/Chain rule)

$g(x) = - x^{81}$ Given

$g'(x) = -81\cdot x^{80}$ (Derivative of a power function)

$h(x) = - x^{2}$ Given

$h'(x) = -2\cdot x$ (Derivative of a power function)

$\frac{d}{dx}[f(x)+g(x)+h(x)] = \frac{9\cdot x^{8}}{\sqrt{1-x^{18}}} - 81\cdot x^{80}-2\cdot x$ (Derivative for a sum of functions/Result)

6 0

3 years ago

in researching her science project, Leigh learned that light travels at a constant rate and that it takes 500 seconds for light

Zielflug [23.3K]

Answer: around 763 seconds

4 0

3 years ago

The probability that Paul wins a raffle is given by the expression n/n+6. Write down an expression, in the form of a combined si

Elza [17]

Answer:

$P(W') = \frac{6}{n+6}$

Step-by-step explanation:

<em>Let P(W) represents the probability that Paul wins</em>

<em>Let P(W') represents the probability that Paul does not win</em>

Given

$P(W) = \frac{n}{n+6}$

Required

$P(W')$

In probability, the sum of opposite probability equals 1;

This implies that

$P(W) + P(W') = 1$

Substitute $P(W) = \frac{n}{n+6}$ in the above equation

$P(W) + P(W') = 1$ becomes

$\frac{n}{n+6}+ P(W') = 1$

Subtract $\frac{n}{n+6}$ from both sides

$\frac{n}{n+6} - \frac{n}{n+6} + P(W') = 1 - \frac{n}{n+6}$

$P(W') = 1 - \frac{n}{n+6}$

Solve fraction (start by taking the LCM)

$P(W') = \frac{n + 6 - n}{n+6}$

$P(W') = \frac{n - n + 6}{n+6}$

$P(W') = \frac{6}{n+6}$

Hence, the probability that Paul doesn't win is $P(W') = \frac{6}{n+6}$

6 0

3 years ago

There were 160 Smarties in the candy box

posledela

27.5 hope that helps

7 0

3 years ago

Need help with this!

katovenus [111]

Answer: x= 10

Step-by-step explanation:

Same side exterior angles sum to 180.

Using this axiom we can say that

142+ (3x+8) = 180

Add like terms on the left side

150+ 3x = 180

Subtract 150 from both sides

3x = 30

Divide both sides by 3

X= 10

8 0

3 years ago