Answer:
If `r` and `R` and the respective radii of the smaller and the bigger semi-circles then the area of the shaded portion in the given figure is: (FIGURE) `pir^2\ s qdotu n i t s` (b) `piR^2-pir^2\ s qdotu n i t s` (c) `piR^2+pir^2\ s qdotu n i t s` (d) `piR^2\ s qdotu n i t s`
Step-by-step explanation:
Answer:
1+1= 2
Step-by-step explanation:
or sometimes people say 11, but irl its 2
Folding a paper will make it thickness become double from it before.
Unfolded paper has 1 thickness
1 times folded paper has 2 thickness
2 times folded paper has 4 thickness
3 times folded paper has 8 thickness
From here it is clear that the pattern is

. SInce the paper is 0.1mm, then the function would be:
f(n)=

x 0.1mm
The nearest whole number would be 18 because the 6 is greater than 5. Anything greater than five, would most likely be rounded to the nearest whole number. Hope this helped!