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ale4655 [162]
3 years ago
10

What is the greatest common factor of 14 and 37?

Mathematics
2 answers:
dem82 [27]3 years ago
8 0

Answer:

1

Step-by-step explanation:

Zinaida [17]3 years ago
5 0

The greatest common factor is 1

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Aryan wants to plant a flower on the ground in the form of a rhombus. The diagonals of the rhombus measures 42 cm and 56 cm. Fin
Vlad1618 [11]

<u>Given</u><u> info</u><u>:</u><u>-</u>

Aryan wants to plant a flower on the ground in the form of a rhombus.The diagonals of the rhombus measures 42 cm and 56 cm.

Find the perimeter of the field ?

<u>Explanation</u><u>:</u><u>-</u>

Given that

rhombus.The diagonals of the rhombus measures 42 cm and 56 cm.

Let consider a rhombus ABCD

Let AC = (d1) = 42 cm

Let BD = (d2) = 56 cm

We know that

The digonals of a rhombus bisects each other at 90°.

AC = AO+OC

⇛ AC = 2 AO = 2 OC

⇛ AO = OC = AC/2

⇛ AO = OC = 42/2 = 21 cm

and

BD = BO+OD

⇛ BD = 2 BO = 2 OD

⇛ BO = OD = BD/2

⇛ BO = OD = 56/2 = 28 cm

We have,

∆AOB is a right angled triangle

By Pythagoras theorem,

AB² = AO²+OB²

⇛ AB² = 21²+28²

⇛ AB² = 441+784

⇛ AB² = 1225

⇛ AB = ±√1225

⇛ AB = ±35

AB is the length of the side which cannot be negative.

AB = 35 cm

We know that

All sides are equal in a rhombus

⇛ AB = BC = CD = DA

As we know

The Perimeter of a rhombus = 4×Side units

The perimeter of the rhombus ABCD

⇛ 4AB = 4BC = 4CD = 4DA

⇛ 4×35 cm

⇛ Perimeter = 140 cm

<em>∴</em><em> </em><em>T</em><em>he perimeter of the given field is 140 cm.</em>

6 0
3 years ago
What is the volume of this rectangular prism
qaws [65]
Volume is 5cm^3 teehee
8 0
3 years ago
Read 2 more answers
Find the lengths of the missing sides in the triangle. Write your answers as integers or as decimals rounded to the nearest tent
nalin [4]

Answer:

The last one (x=11.3, y=8).

Step-by-step explanation:

1) There are three trigonometric ratios for right-angled triangles.

sin()=\frac{opposite}{hypotenuse}\\cos()=\frac{adjacent}{hypotenuse}\\tan()=\frac{opposite}{adjacent}

In a right triangle, the hypotenuse, h, is the side opposite the right angle. Relative to the acute angle θ, check the attachment, the legs are called the opposite side, o, and the adjacent side a.

2) In this case, we are given a length and an angle to find x and y.

Let's find x first. To find x we need to use sin()=\frac{opposite}{hypotenuse}.

sin(45)=\frac{8}{x}\\sin(45)x=8\\x=\frac{8}{sin(45)} \\x=11.31

Find y.

Notice that, we can use the Pythagorean Theorem (c^2=a^2+b^2) to find y.

c^2=a^2+b^2

11.31^2=8^2+b^2\\11.31^2 - 8^2 = b^2\\63.9161 = b^2\\\sqrt{63.9161} = b\\b = 7.99

3) Round them off to the nearest tenth.

x=11.31\\x=11.3

y=7.99\\y=8

Therefore, the correct choice is the last one (x=11.3, y=8).

4 0
2 years ago
Solve each system of equations (systems with 3 variables)
Natasha2012 [34]

Answer:

x = 2 , y = 5 , z = -1 You are correct!!!

Step-by-step explanation:

Solve the following system:

{9 x + 3 y - 4 z = 37 | (equation 1)

4 x + 3 y + 7 z = 16 | (equation 2)

x - 5 y + 8 z = -31 | (equation 3)

Subtract 4/9 × (equation 1) from equation 2:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+(5 y)/3 + (79 z)/9 = (-4)/9 | (equation 2)

x - 5 y + 8 z = -31 | (equation 3)

Multiply equation 2 by 9:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

x - 5 y + 8 z = -31 | (equation 3)

Subtract 1/9 × (equation 1) from equation 3:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

0 x - (16 y)/3 + (76 z)/9 = (-316)/9 | (equation 3)

Multiply equation 3 by 9/4:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

0 x - 12 y + 19 z = -79 | (equation 3)

Add 4/5 × (equation 2) to equation 3:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

0 x+0 y+(411 z)/5 = (-411)/5 | (equation 3)

Multiply equation 3 by 5/411:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Subtract 79 × (equation 3) from equation 2:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y+0 z = 75 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Divide equation 2 by 15:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+y+0 z = 5 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Subtract 3 × (equation 2) from equation 1:

{9 x + 0 y - 4 z = 22 | (equation 1)

0 x+y+0 z = 5 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Add 4 × (equation 3) to equation 1:

{9 x+0 y+0 z = 18 | (equation 1)

0 x+y+0 z = 5 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Divide equation 1 by 9:

{x+0 y+0 z = 2 | (equation 1)

0 x+y+0 z = 5 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Collect results:

Answer:  {x = 2 , y = 5 , z = -1

5 0
3 years ago
PLS SOMEONE HELP ASAP!!
Nataliya [291]
The blue ribbon would be 19 inches. We know the red ribbon is 12 inches and it’s 7 inches less than the blue one, so you would add 7 to 12 to figure out that the blue ribbon is 19 inches.
6 0
3 years ago
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