5 times as many. Since dog B has 2 and dog A has 10, A = 2 * X, since you’re solving for the multiplication comparison. 10/2 = 5, so you’ve got 5 times as many.
60,000 would be the answer because it stays the same if under 5 it stays if above 5 rounds up once
1/3 of all students bring lunch
2:3 is the ratio of students who bring their lunch to the number of students who do not
Answer:
a. False
b. True
Step-by-step explanation:
Given that:
The sample size of the college student n = 100
The population of student that participated p = 38
We are to identify from the following statement if it is true or false.
From part a;
It is false since the random samples not indicate the population perfectly. As such we can't conclude that the proportion of students at this college who participate in intramural sports is 0.38.
The statement in part b is true because the sampling variation, random samples also do not indicate the population perfectly but it is close to be 0.38. Thus, it is suitable to conclude that the proportion of students at this college who participate in intramural sports is likely to be close to 0.38, but not equal to 0.38.
Answer:
and
Step-by-step explanation:
Assume that Mike bought only cookies and hot dogs.
The total can be represented as:
--- (1)
And the amount spent can be represented as:
--- (2)
Required
Determine the system of equation
Let c represents the number of cookies and h, number of hot dogs.
implies
And
Cost of cookies = 0.75 * c
Cost of hot dogs = 1.10 * h
So, we have:
Hence, the equations are:
and
Solving for c and h
Make c the subject in
Substitute 5 - h for c in
Collect Like Terms
Solve for h
-- approximated
Recall that:
