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elena-s [515]
2 years ago
9

One in a thousand people have a particular disease, and the test for the disease is 98% correct in testing for the disease. On t

he other hand, the test has a 1% error rate, if the person being tested, does not have the disease. If someone tests positive, what are the odds they have the disease
Mathematics
1 answer:
USPshnik [31]2 years ago
3 0

The odds a person has the disease they were tested for is 98% or 98:2.

<h3>What is the difference between probability and odds?</h3>

Probability describes how likely is an event to happen by using a percentage from 0 to 100%. On the other hand, the odds focus on the rate between the specific outcome: other outcomes.

<h3>What are the odds in this situation:</h3>

In this case, the specific outcome is to have the disease after being tested, which occurs 98% of the time. This implies only the 2% tested do not have the disease. Now, this relationship can be expressed as:

98: 2

Learn more about odds in: brainly.com/question/545794

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Juli2301 [7.4K]
N would equal 28 since 60-32 is 28
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3 years ago
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Michael uses a uniform probability model for an experiment using a deck of 45 cards. There are 15 blue card, 15 red cards, and 1
vampirchik [111]

Answer:

<em>P</em> = 2/3

Step-by-step explanation:

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15 blue

15 red

15 green

To figure out the probability of red and blue together, add red and blue.

15 + 15 = 30

Since the total is 45, this is how many 30 will be out of.

30 out of 45 = 30/45

Simplify 30/45 by dividing each side by 15

30 ÷ 15 = 2

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30/45 = 2/3

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2 years ago
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PSYCHO15rus [73]
Your answer is 6 over 24 multiplied by 6 over 23.
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2 years ago
What is the value of this expression 1/5-^5?
densk [106]

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7 0
3 years ago
The relative frequency distribution of the number of phobias reported by a hypothetical sample of 500 college students is given
goldenfox [79]

Answer:

a. 0.48

b. 0.14

c. 0.47

Step-by-step explanation:

Data provided in the question

0 - 2        0.48

3 - 5        0.26

6 - 8        0.12

9- 11        0.09

12- 14       0.05

Based on the above information

a. The probability for fewer than three phobias is

= P( x < 3)

= 0.48

b.  The probability for more than eight phobias is

= P( x >8)

= 0.09 + 0.05  

= 0.14

c. Probability between 3 and 11 phobias is  

= P(3 < x < 11)

= 0.26 + 0.12  + 0.09

= 0.47

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3 years ago
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