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elena-s [515]
3 years ago
9

One in a thousand people have a particular disease, and the test for the disease is 98% correct in testing for the disease. On t

he other hand, the test has a 1% error rate, if the person being tested, does not have the disease. If someone tests positive, what are the odds they have the disease
Mathematics
1 answer:
USPshnik [31]3 years ago
3 0

The odds a person has the disease they were tested for is 98% or 98:2.

<h3>What is the difference between probability and odds?</h3>

Probability describes how likely is an event to happen by using a percentage from 0 to 100%. On the other hand, the odds focus on the rate between the specific outcome: other outcomes.

<h3>What are the odds in this situation:</h3>

In this case, the specific outcome is to have the disease after being tested, which occurs 98% of the time. This implies only the 2% tested do not have the disease. Now, this relationship can be expressed as:

98: 2

Learn more about odds in: brainly.com/question/545794

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Solve this equation for x: 2x^2 + 12x - 7 = 0
zhannawk [14.2K]

Answer:

x=0.5355 or x=-6.5355

First step is to: Isolate the constant term by adding 7 to both sides

Step-by-step explanation:

We want to solve this equation: 2x^2 + 12x - 7 = 0

On observation, the trinomial is not factorizable so we use the Completing the square method.

Step 1: Isolate the constant term by adding 7 to both sides

2x^2 + 12x - 7+7 = 0+7\\2x^2 + 12x=7

Step 2: Divide the equation all through by the coefficient of x^2 which is 2.

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Step 3: Divide the coefficient of x by 2, square it and add it to both sides.

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Divided by 2=3

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Therefore, we have:

x^2 + 6x+3^2=\frac{7}{2}+3^2

Step 4: Write the Left Hand side in the form (x+k)^2

(x+3)^2=\frac{7}{2}+3^2\\(x+3)^2=12.5\\

Step 5: Take the square root of both sides and solve for x

x+3=\pm\sqrt{12.5}\\x=-3\pm \sqrt{12.5}\\x=-3+ \sqrt{12.5}, $ or $x= -3- \sqrt{12.5}\\$x=0.5355 or x=-6.5355

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3 years ago
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