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elena-s [515]
3 years ago
9

One in a thousand people have a particular disease, and the test for the disease is 98% correct in testing for the disease. On t

he other hand, the test has a 1% error rate, if the person being tested, does not have the disease. If someone tests positive, what are the odds they have the disease
Mathematics
1 answer:
USPshnik [31]3 years ago
3 0

The odds a person has the disease they were tested for is 98% or 98:2.

<h3>What is the difference between probability and odds?</h3>

Probability describes how likely is an event to happen by using a percentage from 0 to 100%. On the other hand, the odds focus on the rate between the specific outcome: other outcomes.

<h3>What are the odds in this situation:</h3>

In this case, the specific outcome is to have the disease after being tested, which occurs 98% of the time. This implies only the 2% tested do not have the disease. Now, this relationship can be expressed as:

98: 2

Learn more about odds in: brainly.com/question/545794

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What is the value of the 1 in 178
Igoryamba
The value of 1 in 178 is 100 since it is in the hundreds place.  The value of 7 in 178 is 70 and the value of 8 in 178 is 8.  The hundreds place carries numbers from 1 to 9.  Once you get to 10, you add a digit to the number such that you now have four total numbers and the first digit is in the thousands place.
3 0
3 years ago
2. Find the common difference and the recursive formula. a. 22, 19, 16, 13, …
Musya8 [376]

Answer:

The common difference d is d = -3

The recursive formula is: \mathbf{a_n=a_{n-1}-3}

Step-by-step explanation:

We need to find the common difference and the recursive formula.

a. 22, 19, 16, 13, …

First we will find common difference

The formula of arithmetic sequence is: a_n=a_1+(n-1)d

where a_n is nth term, a_1 is 1st term and d is the difference

Looking at the sequence we get: a_1=22, a_2=19

Using these values we can find d, the common difference

a_n=a_1+(n-1)d\\put\:n=2, a_2=19, a_1=22\\19=22+(2-1)d\\19=22+d\\d=19-22\\d=-3

So, the common difference d is d = -3

Now, we will find the recursive formula:

The recursive formula is of type: a_n=a_{n-1}+d

We have found common difference d = -3

So, the recursive formula will be:

a_n=a_{n-1}+d\\a_n=a_{n-1}+(-3)\\a_n=a_{n-1}-3

The recursive formula is: \mathbf{a_n=a_{n-1}-3}

6 0
3 years ago
What is 43.043 in expanded form
nordsb [41]
40+3+.04+.003 

expanded form is showing what you have to add together


3 0
3 years ago
Inverse for f(x)=1/2x+3
Semenov [28]

Answer: f^{-1}(x)=2x-6

Step-by-step explanation:

To find the inverse, we want to switch the y with x and x with y. Once we do that, we solve for y.

y=\frac{1}{2}x+3        [switch x and y]

x=\frac{1}{2}y+3        [subtract both sides by 3]

x-3=\frac{1}{2} y        [multiply both sides by 2]

y=2x-6

Now, we know that  f^{-1}(x)=2x-6.

3 0
3 years ago
Read 2 more answers
Question : In the given figure , ∆ APB and ∆ AQC are equilateral triangles. Prove that PC = BQ.
lorasvet [3.4K]

Answer:

See Below.

Step-by-step explanation:

We are given that ΔAPB and ΔAQC are equilateral triangles.

And we want to prove that PC = BQ.

Since ΔAPB and ΔAQC are equilateral triangles, this means that:

PA\cong AB\cong BP\text{ and } QA\cong AC\cong CQ

Likewise:

\angle P\cong \angle PAB\cong \angle ABP\cong Q\cong \angle QAC\cong\angle ACQ

Since they all measure 60°.

Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:

m\angle PAC=m\angle PAB+m\angle BAC

Likewise:

m\angle QAB=m\angle QAC+m\angle BAC

Since ∠QAC ≅ ∠PAB:

m\angle PAC=m\angle QAC+m\angle BAC

And by substitution:

m\angle PAC=m\angle QAB

Thus:

\angle PAC\cong \angle QAB

Then by SAS Congruence:

\Delta PAC\cong \Delta BAQ

And by CPCTC:

PC\cong BQ

5 0
3 years ago
Read 2 more answers
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