Answer: Required expression:
Result: 
Step-by-step explanation:
Given phrase: 
Required expression:
['+' used to express sum, 'x' used in place of 'of']
Since 18+16 = 34
Then,
![\dfrac14\times(18+16)=\dfrac14\times34 \\\\=\dfrac{1}{2}\times17\ \ \text{[Divide numerator and denominator by 2]}\\\\=\dfrac{17}{2}](https://tex.z-dn.net/?f=%5Cdfrac14%5Ctimes%2818%2B16%29%3D%5Cdfrac14%5Ctimes34%20%20%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes17%5C%20%5C%20%5Ctext%7B%5BDivide%20numerator%20and%20denominator%20by%202%5D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B17%7D%7B2%7D)
Hence,
This deal is cheap! Well, the answer is 60 cents. To get these problems, divide 10.80 by 18, which is equal to 1.5 a dozen.
Answer:
80 miles
Step-by-step explanation:
Answer:
VT = 50√3 , PT = 50
Step-by-step explanation:
Given
PV = 100
With reference angle 60°
hypotenuse (h) = 100
perpendicular (p) = ?
Now
Sin 60° = p/h
√3 / 2 = p / 100
p = √3 * 100 / 2
p = 50√3
Also
With reference angle 30°
hypotenuse (h) = 100
perpendicular (p) = ?
sin 30° = p/h
1/2 = p / 100
p = 100 / 2
p = 50
Hope it will help :)
We have that an inverse variation in a function is given by:

We must find the value of the constant k.
To do this, we substitute the values of x1 = 12, y1 = 15.
We have then:

Clearing k we have:

Substituting the value of k we have that the inverse variation is:

For y2 = 3 we have:

Clearing x2 we have:
Answer: