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3 years ago

Does this figure have symmetry?

Mathematics

1 answer:

marshall27 [118]3 years ago

3 0

No because if you split it in half the halves don’t match

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Solve the equation X/6 +4=16

elena55 [62]

Answer:

$x=160$

Step-by-step explanation:

$\frac{x}{6+4} =16$

$\frac{x}{10} =16$

$x=16 \times 10$

$x=160$

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3 years ago

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Viefleur [7K]

Answer:

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Step-by-step explanation:

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3 years ago

Geometry B Final Exam

Tatiana [17]

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2 years ago

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Find the value of the discriminant for <img src="https://tex.z-dn.net/?f=7x%5E%7B2%7D%20%2B5x%2B1%3D0" id="TexFormula1" title="7

kondor19780726 [428]

Answer:

No real roots

Step-by-step explanation:

Given

7x² + 5x + 1 = 0 ← in standard form

with a = 7, b = 5, c = 1

To determine the nature of the roots use the discriminant

Δ = b² - 4ac

• If b² - 4ac > 0 then roots are real and distinct

• If b² - 4ac = 0 then roots are real and equal

• If b² - 4ac < 0 then the roots are not real

Here

b² - 4ac = 5² - (4 × 7 × 1) = 25 - 28 = - 3

Thus the 2 roots are not real

7 0

3 years ago

A and b are positive integers and a-b=2. Evaluate the following:<br> 9^1/2b/3^a

OlgaM077 [116]

Answer:

$\frac{1}{ 9 }$

Step-by-step explanation:

$\huge \frac{ {9}^{ \frac{1}{2}b } }{ {3}^{a} } \\ \\ = \huge \frac{ {( {3}^{2} )}^{ \frac{1}{2}b } }{ {3}^{a} } \\ \\ = \huge \frac{ { {3}}^{2 \times \frac{1}{2}b } }{ {3}^{a} } \\ \\ \huge = \frac{ {3}^{b} }{ {3}^{a} } \\ \\ \huge = \frac{1}{ {3}^{a - b} } \\ \\ \huge= \frac{1}{ {3}^{2} } \\ ( \because \: a - b = 2)\\ \\ \huge = \frac{1}{ 9 }$

5 0

3 years ago