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Reil [10]
4 years ago
11

Ken recorded the weights (in pounds) of 78 boxes. He created a box plot of his data. What is the interquartile range of Ken’s da

ta? A) 8 Eliminate B) 10 C) 17 D) 48
Mathematics
1 answer:
Serjik [45]4 years ago
8 0

Usatestprep is C) 17

I just took the test

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Find x make sure you simplify your answer
lorasvet [3.4K]

Answer:

h^{2} + 6^{2}=8^{2}

h^{2} + 36 = 64

h^{2} = 64-36

h^{2} = 28

\sqrt{28} = 2\sqrt{7}

h = 5.29

Step-by-step explanation:

8 0
3 years ago
Is this equation true or false 76 + 58= 66 + 48
HACTEHA [7]
The answer is false.
5 0
3 years ago
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REINFORCE Tickets to the zoo cost $18 for adults and $8.25 for children. One day, the zoo sold 2,300 tickets and collected $30,1
jenyasd209 [6]

Given:

The cost of adults ticket = $18

The cost of children's ticket = $8.25

Total tickets = 2300

Total revenue = $30,168.

To find:

The number of children and number of adults attended the zoo that day.

Solution:

Let x be the number of children and y be the number of adults.

Equation for tickets: x+y=2300                  ...(i)

Equation for revenue: 18x+8.25y=30168        ...(ii)

Plot the graphs of the given equations on a coordinate plane as shown below.

From the graph it is clear that the graph of both equations intersect each other at (1148,1152).

It means the number of adults is 1148 and the number of children is 1152.

It can be solved algebraically as shown below:

Substitute the value of y in (ii) from (i).

18x+8.25(2300-x)=30168

18x+18975-8.25x=30168

9.75x=30168-18975

9.75x=11193

Divide both sides by 9.75.

x=\dfrac{11193}{9.75}

x=1148

Putting x=1148 in (i),  we get

1148+y=2300

y=2300-1148

y=1152

Therefore, the number of adults is 1148 and the number of children is 1152.

8 0
3 years ago
i need help please help and dont guess and FYI 492.8 ft is no the answer if you get it right ill give you brainly and I be your
Mandarinka [93]

Answer:

I think it is the fist one bc when you do legth times width you get 308 ft

Step-by-step explanation: please dont get mad at me if im wrong

7 0
3 years ago
Read 2 more answers
Vary the scale factor n from values less than 1 to values greater than 1. How do the points in the resulting images differ from
olya-2409 [2.1K]

Answer: For values of n < 1, all the points on the image move closer to the center of dilation and the logo shrinks. For values of n > 1, all the points on the image move farther from the center of dilation and the logo expands.

Step-by-step explanation: PLATO sample answer. hope it helps :)

5 0
3 years ago
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