The correct question is
The hypotenuse and one of the legs of a right triangle form an angle that has a cosine of √<span>2/2 .
What is the measure of the angle?
Let
</span>∅--------> the angle
cos ∅=√2/2<span>
cos </span>∅=[distance of one of the leg/hypotenuse]
[distance of one of the leg/hypotenuse]=√2/2
<span>I could say that
</span>distance of one of the leg=√2
and
hypotenuse=2
so
<span>applying the Pythagorean theorem
</span>c=hypotenuse=2
a=√2
b=?
c²=a²+b²-------> b²=c²-a²------> b²=2²-(√2)²-----> b²=2-----> b=√2
therefore
if a=b
then
the angle ∅=45°
the answer is the option
<span>b.45 degrees</span>
Answer:
25
Step-by-step explanation:
Step-by-step explanation:
-81
Answer:
y = 4 or y = 6
Step-by-step explanation:
2log4y - log4 (5y - 12) = 1/2
2log_4(y) - log_4(5y-12) = log_4(2) apply law of logarithms
log_4(y^2) + log_4(1/(5y-12)) = log_4(/2) apply law of logarithms
log_4(y^2/(5y-12)) = log_4(2) remove logarithm
y^2/(5y-12) = 2 cross multiply
y^2 = 10y-24 rearrange and factor
y^2 - 10y + 24 = 0
(y-4)(y-6) = 0
y= 4 or y=6
Step-by-step explanation:
Q1 . (f+g)(x) = f(x) + g(x)
=4x-4 +2x^2 -3x
= 2x^2 + x -4
Q2. (f-g)(x) = f(x) - g(x)
= 2x^2−2 - (4x+1)
= 2x^2 -2 -4x -1
= 2x^2 - 4x -3
Q3. h(x)=3x−3 and g(x)=x^2+3
(h.g)(x) = h(x) × g(x)
= (3x-3) × (x^2 + 3)
=3x^3 -3x^2 + 9x -9
Q4.f(x)=x+4 and g(x)=x+6
(f/g)(x) = f(x) ÷ g(x)
= x+4 / x+6
the domain restriction is x>-6
x<-6
x doesn't equal (-6)
