Answer:
7.81 u
Step-by-step explanation:
<u>Given :- </u>
- Two points (3,3) and (-2,-3) is given to us.
And we need to find out the distance between the two points . So , here we can use the distance formula to find out the distance. As,
D = √{(x2-x1)² + (y2-y1)²}
D =√[ (3+2)² +(-3-3)²]
D =√[ 5² +6²]
D =√[ 25 +36]
D = 61
D = 7.81
<h3>Hence the distance between the two points is 7.81 units .</h3>
Answer:
Slope is 1/4
Step-by-step explanation:
Answer: Part A is 2 and 6 Part B is 2
Step-by-step explanation:
Part A: Here is the explanation. So, you started at with the expression 3x^2+8x+4 and when you're are factoring, you have 3x^2+px+pq+4. You can substitute the p and q for 6 and 2. What they did is they replaced 8x with px+qx. To get 8x, p needs to be 6 and q needs to be 2, or the other way around. TIP: The numbers just have to add up to 8 on this one. It doesn't have to be 6 and 2.
Part B: Here is what I got so far... 3x(x+r) is 3x^2+3xr. Also, s(x+r) is sx+sr. The equation becomes, 3x^2+3xr+sx+sr. R can be 2 and s can be 2. Here is my reasoning: The original expression was 3x^2+8x+4. We already have the 3x^2, so now we need to find what the others are by determining what r and s equal. R and s can both be 2 to make four. 2x2 is 4. Let's see if it can make 8. 3xr becomes 6x and sx becomes 2x. 6x+2x is 8x.
Answer: Length = 15 meters
Width = 2 meters
Step-by-step explanation:
Perimeter of a rectangle = 2l + 2w
Area of a rectangle = l × w
where l = length
w = width
Therefore,
2l + 2w = 34 ...... i
l × w = 30 ........ ii
From equation i
2l + 2w = 34
Divide through by 2.
l + w = 17 ...... iii
Then, l = 17 - w ........ iv
Put equation iv into ii
l × w = 30
(17 - w) × w = 30
17w - w² = 30
w² - 17w + 30 = 0
w² - 15w - 2w + 30 = 0
w(w - 15) - 2(w - 15) = 0
(w - 2) = 0
w = 0 + 2 = 2
w - 15 = 0
w = 0 + 15 = 15
Length = 15 meters
Width = 2 meters
Answer:
The area of the shaded region is 42.50 cm².
Step-by-step explanation:
Consider the figure below.
The radius of the circle is, <em>r</em> = 5 cm.
The sides of the rectangle are:
<em>l</em> = 11 cm
<em>b</em> = 11 cm.
Compute the area of the shaded region as follows:
Area of the shaded region = Area of rectangle - Area of circle
![=[l\times b]-[\pi r^{2}]\\\\=[11\times 11]-[3.14\times 5\times 5]\\\\=121-78.50\\\\=42.50](https://tex.z-dn.net/?f=%3D%5Bl%5Ctimes%20b%5D-%5B%5Cpi%20r%5E%7B2%7D%5D%5C%5C%5C%5C%3D%5B11%5Ctimes%2011%5D-%5B3.14%5Ctimes%205%5Ctimes%205%5D%5C%5C%5C%5C%3D121-78.50%5C%5C%5C%5C%3D42.50)
Thus, the area of the shaded region is 42.50 cm².
