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Maru [420]
3 years ago
7

What expression is equivalent to 4 to the power of 4 times 4 to the power of -9

Mathematics
2 answers:
rodikova [14]3 years ago
7 0

Answer:

i tried but i got D

Step-by-step explanation:

zvonat [6]3 years ago
4 0

Answer:

idk this stuff yet

Step-by-step explanation:

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Solve |2x|=8<br> Tell me how you got the answer pls
lilavasa [31]

Answer:

4

Step-by-step explanation:

2 x 4 = 8

Absolute value means no symbols so it would just be 2 x something equals 8 which is 4.

6 0
3 years ago
A 10-inch television has a screen that is 6 inches high. How wide is the screen?
soldier1979 [14.2K]
The television is 60in
3 0
3 years ago
11.15+11.75+10.70 I need some help with this problem
Nina [5.8K]

Answer:

33.60 is your answer

Step-by-step explanation:

Remember to add based on place value.

Note that 10.70 is the same as 10.7

11.15 + 11.75 = 22.90

22.90 + 10.7 = 33.60


<em>~Senpai</em>

3 0
3 years ago
Read 2 more answers
I need help ok i just need help on a few or more things will be sending more
Rzqust [24]
Factors and Multiples. But they both involve multiplication: Factors are what we can multiply to get the number. Multiples are what we get after multiplying the number by an integer (not a fraction).
3 0
3 years ago
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Each year, all final year students take a mathematics exam. It is hypothesised that the population mean score for this test is 1
Yuri [45]

Answer:

90% confidence interval for the population mean test score is [95.40 , 106.59]

Step-by-step explanation:

We are given that the population mean score for mathematics test is 115. It is known that the population standard deviation of test scores is 17.

Also, a random sample of 25 students take the exam. The mean score for this group is 101.

The, pivotal quantity for 90% confidence interval for the population mean test score is given by;

        P.Q. = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, X bar = sample mean = 101

              \sigma = population standard deviation

              n = sample size = 25

So, 90% confidence interval for the population mean test score, \mu is ;

P(-1.6449 < N(0,1) < 1.6449) = 0.90

P(-1.6449 < \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.6449) = 0.90

P(-1.6449 * \frac{\sigma}{\sqrt{n} } < {Xbar-\mu} < 1.6449 * \frac{\sigma}{\sqrt{n} } ) = 0.90

P(X bar - 1.6449 * \frac{\sigma}{\sqrt{n} } < \mu < X bar + 1.6449 * \frac{\sigma}{\sqrt{n} } ) = 0.90

90% confidence interval for \mu = [ X bar - 1.6449 * \frac{\sigma}{\sqrt{n} } , X bar + 1.6449 * \frac{\sigma}{\sqrt{n} } ]

                                                  = [ 101 - 1.6449 * \frac{17}{\sqrt{25} } , 10 + 1.6449 * \frac{17}{\sqrt{25} } ]

                                                  = [95.40 , 106.59]

Therefore, 90% confidence interval for the population mean test score is [95.40 , 106.59] .

7 0
3 years ago
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