It would be the last option. I just worked the problem out and figured it out. I hope this helped! (:
Answer:
7.5 ft³/min
Step-by-step explanation:
Let x be the depth below the surface of the water. The height, h of the water is thus h = 10 - x.
Now, the volume of water V = Ah where A = area of isosceles base of trough = 1/2bh' where b = base of triangle = 4 ft and h' = height of triangle = 1 ft. So, A = 1/2 × 4 ft × 1 ft = 2 ft²
So, V = Ah = 2h = 2(10 - x)
The rate of change of volume is thus
dV/dt = d[2(10 - x)]/dt = -2dx/dt
Since dV/dt = 15 ft³/min,
dx/dt = -(dV/dt)/2 = -15 ft³/min ÷ 2 = -7.5 ft³/min
Since the height of the water is h = 10 - x, the rate at which the water level is rising is dh/dt = d[10 - x]/dt
= -dx/dt
= -(-7.5 ft³/min)
= 7.5 ft³/min
And the height at this point when x = 8 inches = 8 in × 1 ft/12 in = 0.67 ft is h = (10 - 0.67) ft = 9.33 ft
Answer:
8+k2-6>8(k+2)-4k
Step-by-step explanation:
8+7×2-6 and 8(7+2)-4×7
8+14-16 and (56+16)-28
6 and 44
Answer:
28
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
The y-intercept must be at -7, so that eliminates C.
Because of the direction of the line, the slope needs to be negative. This eliminates B.
The slope of the line is -7/6, so D is the correct answer.
